Ajax调用后如何生成弹出窗口 [英] How to generate popup after ajax call

问题描述

我想在ajax调用后生成一个弹出窗口.我当前的代码(如下)将创建一个新标签，而不是一个警报框.

I want to generate a popup after an ajax call. My current code (below) creates a new tab and not alert box.

$.ajax
({
    type: "POST",
    url: "addDayData.php",
    data: TblData,
    async: false,
    success: function (data) {
        window.open("addnewexcursion.php");
    }
});

我应该更改什么以允许新内容显示在弹出窗口中而不是新选项卡中?

What should I change to allow the new content to appear in a popup rather than a new tab?

推荐答案

更好地在弹出窗口中打开"html表单":成功$(#dialog-form").dialog("open");

Better to open a 'html form in popup': On success $( "#dialog-form" ).dialog( "open" );

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