链接jQuery选择器:lt和:gt [英] Chaining jQuery selectors :lt and :gt

问题描述

我有一张桌子有9行以上.

I have a table with more than 9 rows.

如果我这样做:$('table tr:gt(3):lt(6)')，最后我应该收到3个元素还是6个元素，为什么?所有选择器都应用于同一主要选择，还是相继应用于不同选择?

If I do this : $('table tr:gt(3):lt(6)'), shall I receive 3 or 6 elements at the end, and why? Are all selectors applied to the same primary selection, or are they successively applied on different selections?

推荐答案

它们是按顺序应用的，因此首先您将滤除前四个元素(:gt(3))，然后滤除第六个之后的所有元素(:gt(3))已过滤集的:lt(6))元素.

They're applied sequentially, so first you will filter away the first four elements (:gt(3)), then you will filter away all elements after the sixth (:lt(6)) element of the already filtered set.

想象一下这个HTML:

Imagine this HTML:

<br/><br/>
<br/><br/>
<br/><br/>
<br/><br/>
<br/><br/>
<br/><br/>

然后执行以下jQuery:

Then do the following jQuery:

$('br:gt(3):lt(6)').addClass('sel');

您现在将拥有:

<br/><br/>
<br/><br/>
<br class="sel"/><br class="sel"/>
<br class="sel"/><br class="sel"/>
<br class="sel"/><br class="sel"/>
<br/><br/>

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