从META-INF/context.xml获取Web应用程序上下文路径,以产生导航结果 [英] Get the web application context path from META-INF/context.xml to produce an outcome for navigating

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问题描述

我有一个运行在tomcat 8上的primefaces Web应用程序.在META-INF/context.xml中,我定义了以下内容:

I have a primefaces web application running on tomcat 8. In META-INF/context.xml I defined the following:

<?xml version="1.0" encoding="UTF-8"?>
<Context antiJARLocking="true" path="/syslac"/>

在我的xhtml页面中,我有以下片段代码,其中p:commandButton有一个oncomplete标记,它将执行handleLoginRequest函数.

While in my view xhtml page I have this fragment code where p:commandButton has a oncomplete tag that will execute the handleLoginRequest function.

<h:form>
            <h:panelGrid columns="2" cellpadding="5">
               <h:outputLabel for="username" value="Usuario:" />
               <p:inputText value="#{loginBean.usuarioVendedor.usuarioSistema}" id="username" required="true" label="username" />
               <h:outputLabel for="password" value="Contrasena:" />
               <h:inputSecret value="#{loginBean.usuarioVendedor.clave}" id="password" required="true" label="password" />
               <f:facet name="footer">
                  <p:commandButton value="Ingresar" update=":growl" actionListener="#{loginBean.loguearse}" oncomplete="handleLoginRequest(xhr, status, args)" />
               </f:facet>
            </h:panelGrid>
         </h:form>

脚本:

      <script type="text/javascript">function handleLoginRequest(xhr, status, args) 
{
                if (args.validationFailed || !args.loggedIn) {
                    jQuery('#dialog').effect("shake", {times: 2}, 100);
                } else {
                    dlg.hide();
                    jQuery('#loginLink').fadeOut();
                    window.location = args.view;
                }
}
</script>

但是我无法通过logginBean从META-INF/context.xml中检索上下文路径,因此我可以发送导航:/syslac/page.xhtml中window.location要使用的视图arg,其中syslac是应用程序的上下文路径.

But I can not retrieve the context path from META-INF/context.xml through logginBean so that I can send view arg to be used by window.location in navigation: /syslac/page.xhtml where syslac is context path of the application.

推荐答案

上下文路径位于

The context path is in backing bean available by ExternalContext#getRequestContextPath().

String contextPath = FacesContext.getCurrentInstance().getExternalContext().getRequestContextPath();

所以您可以例如:

String loginURI = contextPath + "/login.xhtml";
// ...

请注意,当用作JSF导航结果时,这是完全不必要的.有关正确的方法,请参见底部的第二个另请参阅"链接.

Note that this is completely unnecessary when using as JSF navigation outcome. For the correct approach, see the second "See also" link in bottom.

所以您可以例如:

<h:outputScript>
    // ...
    window.location = "#{request.contextPath}" + args.view;
</h:outputScript>

或者当脚本位于.js文件中时(正确的做法!):

Or when your script is in a .js file (correct practice!):

<html lang="en" data-baseuri="#{request.contextPath}">

window.location = document.documentElement.dataset.baseuri + args.view;

另请参见:

  • 如何获取基本URL?
  • 要用于链接/的URL导航到其他JSF页面
  • See also:

    • How get the base URL?
    • What URL to use to link / navigate to other JSF pages
    • 这篇关于从META-INF/context.xml获取Web应用程序上下文路径,以产生导航结果的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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