根据列名称列表在h:dataTable中创建h:column组件 [英] Create h:column components inside h:dataTable based on a list of column names

问题描述

我正在尝试使用两个列表创建一个<h:dataTable>.一个列表包含列名，另一列表包含将填充表的数据.我需要包含列名的列表，因为第二个中的数据具有比我想显示的更多的属性.我该如何实现?

I'm trying to create a <h:dataTable> using two lists. One list contains the column names and the other one contains the data that will populate the table. I need the list containing the column names because the data in the second one has more attributes than I'd like to display. How can I achieve this?

推荐答案

是的，如果使用<c:forEach>遍历列名并生成<h:dataTable>所需的<h:column>组件，则可以.您可以在EL中使用大括号符号[]将列名用作动态" bean属性名(甚至用作Map键).

Yes, you can if you use <c:forEach> to iterate over the column names and generate the <h:column> components necessary for <h:dataTable>. You can use the brace notation [] in EL to use the column name as a "dynamic" bean property name (or even as a Map key).

<h:dataTable value="#{bean.rows}" var="row">
    <c:forEach items="#{bean.columnNames}" var="columnName">
        <h:column>#{row[columnName]}</h:column>
    </c:forEach>
</h:dataTable>

这篇关于根据列名称列表在h:dataTable中创建h:column组件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！