Java EE Web应用程序中的动态目录 [英] Dynamic Directory in Java EE Web Application
问题描述
我创建了一个使用JSF的Java EE应用程序.在我的web目录中，我有一个名为index.xhtml的文件.我的目标是根据父目录的名称在此网页上提供不同的内容.
I have created a Java EE application that uses JSF. In my web directory, I have a file named index.xhtml. My goal is to serve different content on this webpage based upon the parent directory's name.
例如:
http://localhost:8080/myapp/1/index.xhtml将打印You accessed through "1".
http://localhost:8080/myapp/1234/index.xhtml将打印You accessed through "1234".
我不想为每个可能的号码创建目录；它应该是完全动态的.
I do not want to create a directory for every single possible number; it should be completely dynamic.
此外，我需要我的导航规则仍然可以使用.因此，如果我有这样的导航规则:
Additionally, I need my navigation rules to still be usable. So if I have a navigation rule such as this:
<navigation-rule>
<display-name>*</display-name>
<from-view-id>*</from-view-id>
<navigation-case>
<from-outcome>index</from-outcome>
<to-view-id>/index.xhtml</to-view-id>
<redirect />
</navigation-case>
</navigation-rule>
然后，如果我位于目录1234中，它将仍然重定向到index.xhtml页面 1234中.
Then if I am in the directory 1234, it will still redirect to the index.xhtml page within 1234.
这可能吗?我该怎么办?
Is this possible? How can I do this?
推荐答案
为了将/[number]/index.xhtml转发到/index.xhtml，从而将[number]存储为请求属性，您需要servlet过滤器. doFilter()实现可以如下所示:
In order to forward /[number]/index.xhtml to /index.xhtml whereby [number] is been stored as a request attribute, you need a servlet filter. The doFilter() implementation can look like this:
@WebFilter("/*")
public class YourFilter implements Filter {
@Override
public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException {
HttpServletRequest request = (HttpServletRequest) req;
String[] paths = request.getRequestURI().substring(request.getContextPath().length()).split("/");
if (paths.length == 3 && paths[2].equals("index.xhtml") && paths[1].matches("[0-9]{1,9}")) {
request.setAttribute("directory", Integer.valueOf(paths[1]));
request.getRequestDispatcher("/index.xhtml").forward(req, res);
}
else {
chain.doFilter(req, res);
}
}
// ...
}
确保该数字与1到9个拉丁数字匹配，并将其存储为由directory标识的请求属性，最后转发到上下文根中的/index.xhtml.如果没有其他问题，它只会继续请求，就好像什么都没发生一样.
It makes sure the number matches 1 to 9 latin digits and stores it as a request attribute identified by directory and finally forwards to /index.xhtml in context root. If nothing maches, it simply continues the request as if nothing special happened.
在/index.xhtml中，您可以通过#{directory}访问该号码.
In the /index.xhtml you can access the number by #{directory}.
<p>You accessed through "#{directory}"</p>
然后，为了确保JSF导航(和<h:form>！)能够正常工作，您需要自定义
Then, in order to make sure JSF navigation (and <h:form>!) keeps working, you need a custom view handler which overrides the getActionURL() to prepend the URL with the path represented by directory request attribute, if any. Here's a kickoff example:
public class YourViewHandler extends ViewHandlerWrapper {
private ViewHandler wrapped;
public YourViewHandler(ViewHandler wrapped) {
this.wrapped = wrapped;
}
@Override
public String getActionURL(FacesContext context, String viewId) {
String actionURL = super.getActionURL(context, viewId);
if (actionURL.endsWith("/index.xhtml")) {
Integer directory = (Integer) context.getExternalContext().getRequestMap().get("directory");
if (directory != null) {
actionURL = actionURL.substring(0, actionURL.length() - 11) + directory + "/index.xhtml";
}
}
return actionURL;
}
@Override
public ViewHandler getWrapped() {
return wrapped;
}
}
要使其运行，请在faces-config.xml中进行如下注册.
In order to get it to run, register in faces-config.xml as below.
<application>
<view-handler>com.example.YourViewHandler</view-handler>
</application>
这也是JSF定位的URL重写引擎(例如 PrettyFaces )工作的方式.
This is also pretty much how JSF targeted URL rewrite engines such as PrettyFaces work.
- How to use a servlet filter in Java to change an incoming servlet request url?
- How to create user-friendly and seo-friendly urls in jsf?
- Get rewritten URL with query string
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