测试两个JSON对象的相等性，忽略Java中的子顺序 [英] Testing two JSON objects for equality ignoring child order in Java

问题描述

我正在寻找一个JSON解析库，该库支持比较两个JSON对象而不考虑子顺序，特别是对从Web服务返回的JSON进行单元测试.

I'm looking for a JSON parsing library that supports comparing two JSON objects ignoring child order, specifically for unit testing JSON returning from a web service.

任何主要的JSON库都支持吗? org.json库仅进行参考比较.

Do any of the major JSON libraries support this? The org.json library simply does a reference comparison.

推荐答案

作为一般体系结构的观点，我通常建议不要让对特定序列化格式的依赖关系超出存储/网络层的范围.因此，我首先建议您考虑测试自己的应用程序对象之间的相等性，而不是它们的JSON表现形式.

As a general architectural point, I usually advise against letting dependencies on a particular serialization format bleed out beyond your storage/networking layer; thus, I'd first recommend that you consider testing equality between your own application objects rather than their JSON manifestations.

话虽如此，我目前是 Jackson 的忠实拥护者，我迅速阅读了他们的 ObjectNode.equals()实施建议您进行所需的集合成员资格比较:

Having said that, I'm currently a big fan of Jackson which my quick read of their ObjectNode.equals() implementation suggests does the set membership comparison that you want:

public boolean equals(Object o)
{
    if (o == this) return true;
    if (o == null) return false;
    if (o.getClass() != getClass()) {
        return false;
    }
    ObjectNode other = (ObjectNode) o;
    if (other.size() != size()) {
        return false;
    }
    if (_children != null) {
        for (Map.Entry<String, JsonNode> en : _children.entrySet()) {
            String key = en.getKey();
            JsonNode value = en.getValue();

            JsonNode otherValue = other.get(key);

            if (otherValue == null || !otherValue.equals(value)) {
                return false;
            }
        }
    }
    return true;
}

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