如何在PHP中访问JSON解码数组 [英] How to access JSON decoded array in PHP

问题描述

我从javascript到PHP返回了一个JSON数据类型的数组，我使用json_decode($data, true)将其转换为关联数组，但是当我尝试使用关联index使用它时，我收到错误"Undefined index"返回的数据如下:

I returned an array of JSON data type from javascript to PHP, I used json_decode($data, true) to convert it to an associative array, but when I try to use it using the associative index, I get the error "Undefined index" The returned data looks like this

array(14) { [0]=> array(4) { ["id"]=> string(3) "597" ["c_name"]=> string(4) "John" ["next_of_kin"]=> string(10) "5874594793" ["seat_no"]=> string(1) "4" } 
[1]=> array(4) { ["id"]=> string(3) "599" ["c_name"]=> string(6) "George" ["next_of_kin"]=> string(7) "6544539" ["seat_no"]=> string(1) "2" } 
[2]=> array(4) { ["id"]=> string(3) "601" ["c_name"]=> string(5) "Emeka" ["next_of_kin"]=> string(10) "5457394839" ["seat_no"]=> string(1) "9" } 
[3]=> array(4) { ["id"]=> string(3) "603" ["c_name"]=> string(8) "Chijioke" ["next_of_kin"]=> string(9) "653487309" ["seat_no"]=> string(1) "1" }  

请，我如何在PHP中访问这样的数组?感谢您的任何建议.

Please, how do I access such array in PHP? Thanks for any suggestion.

推荐答案

当您将true作为第二个参数传递给json_decode时，在上面的示例中，您可以检索类似于以下内容的数据:

As you're passing true as the second parameter to json_decode, in the above example you can retrieve data doing something similar to:

$myArray = json_decode($data, true);
echo $myArray[0]['id']; // Fetches the first ID
echo $myArray[0]['c_name']; // Fetches the first c_name
// ...
echo $myArray[2]['id']; // Fetches the third ID
// etc..

如果您不将true作为第二个参数传递给json_decode，则会将其作为对象返回:

If you do NOT pass true as the second parameter to json_decode it would instead return it as an object:

echo $myArray[0]->id;

这篇关于如何在PHP中访问JSON解码数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！