用其他字符串替换JSON的一部分(使用字符串令牌) [英] Replace part of a JSON with other (using a string token)
问题描述
我遇到了一个无法解决的问题,我在不同的地方搜寻,但是我仍然找不到它.
I'm having an issue that I cant fix, I seek and seek in different places, but I still without find it.
查看此代码:
//I have 2 json to merge
var json = @"{'client': {'name': 'Should NO CHANGE', 'lastname': '', 'email': 'asd@asd.com', 'phone': '', 'birthday': '', 'married': false, 'spouse': {'name': '', 'lastname': ''} } }";
var json2 = @" {'client': {'name': 'aaaa', 'lastname': 'bbbb', 'email': 'cccccc@ccccc.com', 'phone': '', 'birthday': '', 'married': false, 'spouse': {'name': 'dddddd', 'lastname': 'eeeee'} } } ";
//for example to properties to replace
var path = "client.spouse";
var path2 = "client.email";
dynamic o1 = JObject.Parse(json);
dynamic o2 = JObject.Parse(json2);
//I want this, but using the string (LIKE REFLECTION)
// NOT THE DYNAMIC object
// Can be a simple property or a complex object
o1.client.spouse = o2.client.spouse;
o1.client.email = o2.client.email;
我需要使用字符串而不是"o1.client.email"来替换内容.因为可以是任何东西. (而且json可以是任何东西)
I need to use a string instead of "o1.client.email" to replace the content. Because can be anything. (also the json can be anything)
我可以用字符串,动态或任何可行的方式代替.
I can replace by strings, by dynamic, or whatever it work.
(XML有效,但是当是日期,布尔值或数字时,我丢失了数据类型)
(XML works, but I lost the data type when is a date, boolean or numeric)
NetFiddle 中的示例.
推荐答案
您可以使用 SelectToken
以选择JSON对象层次结构中的任何项目.它支持 JSONPath查询语法.它返回与所选项目的值相对应的JToken
,如果找不到,则返回null
.该JToken
依次具有 Replace(JToken replacement)
方法.因此,您可以执行以下操作:
You can use SelectToken
to select any item in the JSON object hierarchy. It supports JSONPath query syntax. It returns a JToken
corresponding to the value of the selected item, or null
if not found. That JToken
in turn has a Replace(JToken replacement)
method. Thus you can do:
var o1 = JObject.Parse(json);
var o2 = JObject.Parse(json2);
var path = "client.spouse";
o1.SelectToken(path).Replace(o2.SelectToken(path));
var path2 = "client.email";
o1.SelectToken(path2).Replace(o2.SelectToken(path2));
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