如何使用jQuery对JSON数据进行分页? [英] How to use jQuery to paginate JSON data?

查看:109
本文介绍了如何使用jQuery对JSON数据进行分页?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

重复:

很好的jquery分页插件,可用于json数据…

我的JSON数据如下

{
    "Table": [{
        "Emp_Id": "3",
        "Identity_No": "",
        "Emp_Name": "Jerome",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Supervisior",
        "Desig_Description": "Supervisior of the Construction",
        "SalaryBasis": "Monthly",
        "FixedSalary": "25000.00"
    }, {
        "Emp_Id": "4",
        "Identity_No": "",
        "Emp_Name": "Mohan",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Acc ",
        "Desig_Description": "Accountant",
        "SalaryBasis": "Monthly",
        "FixedSalary": "200.00"
    }, {
        "Emp_Id": "5",
        "Identity_No": "",
        "Emp_Name": "Murugan",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason",
        "Desig_Description": "Mason",
        "SalaryBasis": "Weekly",
        "FixedSalary": "150.00"
    }, {
        "Emp_Id": "6",
        "Identity_No": "",
        "Emp_Name": "Ram",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason",
        "Desig_Description": "Mason",
        "SalaryBasis": "Weekly",
        "FixedSalary": "120.00"
    }, {
        "Emp_Id": "7",
        "Identity_No": "",
        "Emp_Name": "Raja",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason",
        "Desig_Description": "Mason",
        "SalaryBasis": "Weekly",
        "FixedSalary": "135.00"
    }, {
        "Emp_Id": "8",
        "Identity_No": "",
        "Emp_Name": "Raja kumar",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason Helper",
        "Desig_Description": "Mason Helper",
        "SalaryBasis": "Weekly",
        "FixedSalary": "105.00"
    }, {
        "Emp_Id": "9",
        "Identity_No": "",
        "Emp_Name": "Lakshmi",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason Helper",
        "Desig_Description": "Mason Helper",
        "SalaryBasis": "Weekly",
        "FixedSalary": "100.00"
    }, {
        "Emp_Id": "10",
        "Identity_No": "",
        "Emp_Name": "Palani",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Carpenter",
        "Desig_Description": "Carpenter",
        "SalaryBasis": "Weekly",
        "FixedSalary": "200.00"
    }, {
        "Emp_Id": "11",
        "Identity_No": "",
        "Emp_Name": "Annamalai",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Carpenter",
        "Desig_Description": "Carpenter",
        "SalaryBasis": "Weekly",
        "FixedSalary": "220.00"
    }, {
        "Emp_Id": "12",
        "Identity_No": "",
        "Emp_Name": "David",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Steel Fixer",
        "Desig_Description": "Steel Fixer",
        "SalaryBasis": "Weekly",
        "FixedSalary": "220.00"
    }, {
        "Emp_Id": "13",
        "Identity_No": "",
        "Emp_Name": "Chandru",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Steel Fixer",
        "Desig_Description": "Steel Fixer",
        "SalaryBasis": "Weekly",
        "FixedSalary": "220.00"
    }, {
        "Emp_Id": "14",
        "Identity_No": "",
        "Emp_Name": "Mani",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Steel Helper",
        "Desig_Description": "Steel Helper",
        "SalaryBasis": "Weekly",
        "FixedSalary": "175.00"
    }, {
        "Emp_Id": "15",
        "Identity_No": "",
        "Emp_Name": "Karthik",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Wood Fixer",
        "Desig_Description": "Wood Fixer",
        "SalaryBasis": "Weekly",
        "FixedSalary": "195.00"
    }, {
        "Emp_Id": "16",
        "Identity_No": "",
        "Emp_Name": "Bala",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Wood Fixer",
        "Desig_Description": "Wood Fixer",
        "SalaryBasis": "Weekly",
        "FixedSalary": "185.00"
    }, {
        "Emp_Id": "17",
        "Identity_No": "",
        "Emp_Name": "Tamil arasi",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Wood Helper",
        "Desig_Description": "Wood Helper",
        "SalaryBasis": "Weekly",
        "FixedSalary": "185.00"
    }, {
        "Emp_Id": "18",
        "Identity_No": "",
        "Emp_Name": "Perumal",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Cook",
        "Desig_Description": "Cook",
        "SalaryBasis": "Weekly",
        "FixedSalary": "105.00"
    }, {
        "Emp_Id": "19",
        "Identity_No": "",
        "Emp_Name": "Andiappan",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Watchman",
        "Desig_Description": "Watchman",
        "SalaryBasis": "Weekly",
        "FixedSalary": "150.00"
    }]
}

此JSON数据中有22条记录.如何使用jQuery将JSON数据分页为每页5个?

There are 22 records in this JSON data. How to paginate this JSON data to 5 per page using jQuery?

替代文本http://img218.imageshack.us/img218/7757/fivej .jpg

上图是我使用jQuery迭代的员工列表的摘要视图.

The above image is my summary view of employee list iterated using jQuery.

var jsonObj = JSON.parse(HfJsonValue);
    for (var i = jsonObj.Table.length - 1; i >= 0; i--) {
        var employee = jsonObj.Table[i];
        $('<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>').insertAfter('#ResultsDiv');
    }

我得到22条记录.现在它可能会增长.如何使用jQuery分页对JSON数据进行分页?

I get 22 records. Now it may grow. How to paginate the JSON data by using jQuery pagination?

推荐答案

您可以使用Array.splice方法从数组中创建所需大小的组:

You can use the Array.splice-method to create groups of the size you want from the array:

// Parse json etc.
var json = [...];
// Fetch the data for a page from the json-result object
var page = 1,
    recPerPage = 5,
    // Use Math.max to ensure that we at least start from record 0
    startRec = Math.max(page - 1, 0) * 5,
    // The end index of Array.splice doesn't have to be within boundaries,
    // But if you want to ensure that it does, then use 
    // Math.min(startRec + recPerPage, json.table.length)
    endRec = startRec + recPerPage
    recordsToShow = json.table.splice(startRec, endRec);

recordsToShow现在包含要显示在页面上的记录数组.重构page = 1并将其作为参数,并对recPerPage = 5进行相同的操作,您应该会做得很好.您可以使用jQuery.each遍历recordsToShow,并使用某种模板系统从每条记录创建HTML元素.

recordsToShow now contains an array of records to show for a page. Refactor out page = 1 and take it as a parameter, and do the same for recPerPage = 5, and you should be good to go. You can use jQuery.each to iterate through recordsToShow, and use some kind of templating system to create HTML-elements from each record.

您还应该向startRec添加某种检查,以确保起始记录在边界内.如果不是,则显示第1页,或向用户显示错误消息.

You should also add some kind of check to startRec to ensure that the starting record is within boundaries. If it is not, then either display page 1, or display an error message to the user.

这篇关于如何使用jQuery对JSON数据进行分页?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆