Python请求-从response.text中提取数据 [英] Python requests - extracting data from response.text
问题描述
我已经环顾了几天,无法解决这个问题.基本上,我是将图像上传到服务器并获得ID作为回报,问题是我无法弄清楚如何提取此ID并将其更改为准备好保存到数据库中的字符串.
I have been looking around for a few days now and cannot figure this out. Basically I'm uploading an image to a server and get an ID in return, the problem is I cannot figure out how to extract this ID and change it into a String ready to be saved into a database.
程序代码
url = <Server address>
with open("image.jpg", "rb") as image_file:
files = {'file': image_file}
auth = ('<Key>', '<Pass>')
r = requests.post(url, files=files, auth=auth)
data = r.json()
uploaded = data.get('uploaded')
content_id = uploaded[0]
print r
print r.text
print '--------------'
print str(content_id)
这是我得到的输出
<Response [200]>
{
"status": "success",
"uploaded": [
{
"filename": "image.jpg",
"id": "6476edfa1d262ad81181d992da78149d"
}
]
}
--------------
{u'id': u'6476edfa1d262ad81181d992da78149d', u'filename': u'image.jpg'}
推荐答案
您正在接收JSON;您已经使用response.json()
方法将其解码为Python结构:
You are receiving JSON; you already use the response.json()
method to decode that to a Python structure:
data = r.json()
您可以将data['uploaded']
视为任何其他Python列表;内容只是一个字典,因此另一个字典键可获取id
值:
You can treat data['uploaded']
as any other Python list; the content is just the one dictionary, so another dictionary key to get the id
value:
data['uploaded'][0]['id']
在这里,将索引硬编码为[0]
是安全的,因为您知道您上传了多少张图片.
It is safe to hardcode the index to [0]
here as you know how many images you uploaded.
您可以使用异常处理来检测是否返回了意外内容:
You could use exception handling to detect if anything unexpected was returned:
try:
image_id = data['uploaded'][0]['id']
except (IndexError, KeyError):
# key or index is missing, handle an unexpected response
log.error('Unexpected response after uploading image, got %r',
data)
或者您可以处理data['status']
;这完全取决于您在此使用的API的确切语义.
or you could handle data['status']
; it all depends on the exact semantics of the API you are using here.
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