PHP的JSON解码包含破折号的变量 [英] php json decode with variables that contains dashes

问题描述

{"general":{
 "round-corner":"0",
 "border-stroke":"2",
 "background-color":"#ffffff"
 }
}

我有这个json字符串，我知道php变量名称不支持破折号.那么在这种情况下该怎么办?

I have this json string, I know that php variable names doesn't support dashes. So what to do in this case ?

推荐答案

您可以使用像这样的数组格式.连字符的键将起作用.

You can use an array format like this. Hyphened keys will work.

<?php

$json = '{"general":{
 "round-corner":"0",
 "border-stroke":"2",
 "background-color":"#ffffff"
 }
}';

$array = json_decode($json, true);

echo $array['general']['border-stroke']; // prints 2

?>

这是演示

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