在Newtonsoft.Json库中获取Raw json字符串 [英] Get Raw json string in Newtonsoft.Json Library
问题描述
我有这样的json
{
"name": "somenameofevent",
"type": "event",
"data": {
"object": {
"age": "18",
"petName": "18"
},
"desct": {
}
}
}
我有2个这样的对象
public class CustEvent
{
[JsonProperty("name")]
public string Name { get; set; }
[JsonProperty("type")]
public string EventType{ get; set; }
[JsonProperty("data")]
public SomeData Data{ get; set; }
}
public class SomeData
{
[JsonProperty("object")]
public String SomeObject { get; set;}
[JsonProperty("dsct")]
public String SomeDesct { get; set; }
}
我用来解析json以成为Newtonsoft.NET库的对象.以及如何将RAW JSON转换为SomeObject和SomeDesct属性?在JSON中,"data.object ..."是复杂的对象,我只想将RAW JSON String转换为这些属性.你能帮我吗?
I use to parse json to object Newtonsoft.NET library. And how i can get RAW JSON into SomeObject , SomeDesct properties ? In JSON "data.object ..." are complex object and i want to get only RAW JSON String to those properties. Can you help me ?
推荐答案
You don't need to write any converters, just use the JRaw
type as follows:
public class SomeData
{
[JsonProperty("object")]
public JRaw SomeObject { get; set;}
[JsonProperty("dsct")]
public JRaw SomeDesct { get; set; }
}
然后,您可以通过检查.Value
属性来访问原始值:
Then you can access the raw value by checking the .Value
property:
var rawJsonDesct = (string)data.SomeDesct.Value;
如果要保留string
签名,只需将JSON序列化为隐藏属性,然后在accessor调用中进行字符串转换即可.
If you want to retain the string
signature, just serialize the JSON to a hidden property and have the string conversion in the accessor call instead.
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