如何通过3对多关系表将数组与MySQL连接 [英] How to join arrays with MySQL from 3 tables of many-to-many relationship

问题描述

我在本地服务器上使用phpMyAdmin创建了一个mySQL数据库.在这个数据库中，我存储了我的朋友的名字和最喜欢的NBA球队，这显然是多对多的关系.因此，我在MySQL中运行以下脚本来为此数据库创建适当的表:

I created a mySQL database with phpMyAdmin in my local server. In this database I store the names and the favourite NBA teams of my friends.This is obviously a many-to-many relationship. For this reason, I run the followed script in MySQL to create the appropriate tables for this database:

CREATE TABLE `friends` (
  `id` int(4) NOT NULL AUTO_INCREMENT,
  `name` varchar(30) NOT NULL,
  PRIMARY KEY (`id`)
)

CREATE TABLE `teams` (
  `id` int(4) NOT NULL AUTO_INCREMENT,
  `name` varchar(30) NOT NULL,
  PRIMARY KEY (`id`)
)

CREATE TABLE `relations` (
  `friends_id` int(4) NOT NULL,
  `teams_id` int(4) NOT NULL,
)

很显然，我在这些表中插入了一些值，但是为了节省空间，在这里我没有广泛提供源代码.一小部分内容如下:

Obviously, I inserted some values to these tables but I do not provide extensively the source code here so as to save some space. An small piece of it is the following:

INSERT INTO `friends` (`id`, `name`)
VALUES
    (1,'David Belton'),
    (2,'Alex James');

INSERT INTO `teams` (`id`, `name`)
VALUES
    (1,'Cleveland Cavaliers'),
    (2,'Boston Celtics');

INSERT INTO `relations` (`friends_id`, `teams_id`)
VALUES
    (1,1),
    (2,1),
    (2,2);

运行一个从数据库中获取数据并打印它们的PHP脚本之后，我想为我的每个朋友提供以下有效的json输出:

After running a PHP script that fetches the data from the database and print them, I want to have the following kind of valid json output for each of my friends:

{
    "id": "1",
    "name": "Alex James",
    "team": ["Boston Celtics", "Cleveland Cavaliers"] 
}

我怎样才能使每个使用MySQL的人都喜欢的团队呢?

How can I make this array of favourite teams for each person with MySQL?

P.S. 我以为最好在使用PHP检索数据之前在MySQL中完成此操作.

P.S. I presuppose that this is better to be done in MySQL before the data are retrieved with PHP.

推荐答案

简便"方法是使用CONCAT生成JSON.
并使用GROUP_CONCAT将多个团队记录合并到一个JSON数组中.
该方法还可以在不支持创建JSON函数的MySQL较早版本中使用.

The "eazy" method is to use CONCAT to generate JSON.
And use GROUP_CONCAT to combine the multiple teams records into a JSON array.
This methode also works in the older MySQL versions that don't support create JSON functions.

查询

SET SESSION group_concat_max_len = @@max_allowed_packet

SELECT 
 CONCAT(
     "{"
   ,     '"id"' , ":" , '"' , friends.id , '"' , ","
   ,     '"name"' , ":" , '"' , friends.name , '"' , ","
   ,     '"team"' , ":" , "["
                              , GROUP_CONCAT('"', teams.name, '"')
                        , "]"
   , "}"
   ) AS json
FROM 
 friends 
INNER JOIN 
 relations 
ON 
 friends.id = relations.friends_id
INNER JOIN
 teams 
ON
 relations.teams_id = teams.id
WHERE 
 friends.id = 1

结果

|                                                            json |
|-----------------------------------------------------------------|
| {"id":"1","name":"David Belton","team":["Cleveland Cavaliers"]} |

演示

http://www.sqlfiddle.com/#!9/4cd244/19

编辑了更多朋友

查询

SET SESSION group_concat_max_len = @@max_allowed_packet

SELECT
  CONCAT(
      "["
    , GROUP_CONCAT(json_records.json) # combine json records into a string
    , "]"
  )  AS json
FROM (

  SELECT 
     CONCAT(
       "{"
     ,     '"id"' , ":" , '"' , friends.id , '"' , ","
     ,     '"name"' , ":" , '"' , friends.name , '"' , ","
     ,     '"team"' , ":" , "["
                              , GROUP_CONCAT('"', teams.name, '"')
                          , "]"
     , "}"
     ) AS json 
  FROM 
    friends 
  INNER JOIN 
    relations 
  ON 
    friends.id = relations.friends_id
  INNER JOIN
    teams 
  ON
    relations.teams_id = teams.id
  WHERE 
    friends.id IN(SELECT id FROM friends) #select the friends you need or just simply friends.id IN(1, 2)
  GROUP BY
     friends.id
) 
 AS json_records

结果

|                                                                                                                                             json |
|--------------------------------------------------------------------------------------------------------------------------------------------------|
| [{"id":"1","name":"David Belton","team":["Cleveland Cavaliers"]},{"id":"2","name":"Alex James","team":["Boston Celtics","Cleveland Cavaliers"]}] |

演示

http://www.sqlfiddle.com/#!9/4cd244/61

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