移动对象沿着直线 [英] Move Object along a straight line

问题描述

我试图沿直线路径移动雪碧。我想它每次我经过的方法，直到我到达终点移动5个像素的斜坡上，或斜边。

我有坡度，线的y轴截距，我也有过的getX（）和对的getY精灵当前X和Y值（）。最后的X和Y点，停在是变量finalX和finalY。

我已经尝试了这么多的方程，但我似乎无法得到其中的任何工作。我缺少什么！？

我最近的方程，试图使用表达式y = mx + B。

 浮动X =（的getY（）+ 5  -  interceptY）/斜率;
浮Y =斜率*（的getX（）+ 5）+ interceptY;
的setPosition（X，Y）;
 

解决方案

能帮你从我最近的比赛几个等式中，code移动物体赋予其旋转：

 浮法x方向= FloatMath.sin（（浮点）Math.toRadians（getRotation（）））
            * 现在的速度;
浮yDirection = FloatMath.cos（（浮点）Math.toRadians（getRotation（）））
            * -现在的速度;浮下一页末=的getX（）+ x方向;
浮newy指定的getY =（）+ yDirection;
 

您只需要获得中，你需要你的精灵移动的角度，这会为你做。希望这有助于。

I am trying to move a Sprite along a straight line path. I want to move it 5 pixels on the slope, or the hypotenuse each time I go through the method until I reach the end point.

I have the slope and y-intercept of the line, I also have the current X and Y values of the sprite through getX() and getY(). The final X and Y points to stop at are variables finalX and finalY.

I have tried so many equations but I can't seem to get any of them to work. What am I missing!!?

My latest equation was trying to use y=mx+b.

float X = (getY() + 5 - interceptY)/slope;
float Y = slope*(getX() + 5) + interceptY;
setPosition(X, Y);

解决方案

Can help you with a few equations from my recent game, the code moves an object given its rotation:

float xDirection = FloatMath.sin((float) Math.toRadians(getRotation()))
            * currentSpeed;
float yDirection = FloatMath.cos((float) Math.toRadians(getRotation()))
            * -currentSpeed;

float newX = getX() + xDirection;
float newY = getY() + yDirection;

You just need to derive the angle in which you need your sprite to move and this will do for you. Hope this helps.

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