如何创建具有多个密钥的NSDictionary? [英] How to create an NSDictionary with multiple keys?

问题描述

我不确定我要问的是否实际上是具有多个键但可以的NSDictionary.

I am not sure if what I am going to ask is actually an NSDictionary with multiple keys but ok.

我想做的是用数据的键和值创建一个NSDictionary，然后将其转换为JSON格式. JSON格式看起来完全像这样:

What I want to do is create an NSDictionary with keys and values for my data and then convert it to JSON format. The JSON format would look exactly like this :

{
    "eventData": {
        "eventDate": "Jun 13, 2012 12:00:00 AM",
        "eventLocation": {
            "latitude": 43.93838383,
            "longitude": -3.46
        },
        "text": "hjhj",
        "imageData": "raw data",
        "imageFormat": "JPEG",
        "expirationTime": 1339538400000
    },
    "type": "ELDIARIOMONTANES",
    "title": "accIDENTE"
}

我只这样使用NSDictionaries:

NSArray *keys = [NSArray arrayWithObjects:@"eventDate", @"eventLocation", @"latitude"  nil];
NSArray *objects = [NSArray arrayWithObjects:@"object1", @"object2", @"object3", nil]; 
dictionary = [NSDictionary dictionaryWithObjects:objects forKeys:keys];

但是以上格式并不完全是关于键-值的. 所以我的问题是NSDictionary是什么，以适应JSON格式? 感谢您阅读我的文章，并感到困惑.

But the above format is not all about key - value. So my question is how would the NSDictionary be , to fit the JSON format?? Thanks for reading my post , and sorry if any confusion.

推荐答案

您可以在另一个NSDictonary中包含一个NSDictionary:

You can have a NSDictionary inside another NSDictonary:

NSDictionary *eventLocation = [NSDictionary dictionaryWithObjectsAndKeys:@"43.93838383",@"latitude",@"-3.46",@"latitude", nil];

NSMutableDictionary *eventData = [NSDictionary dictionaryWithObjectsAndKeys:eventLocation,@"eventLocation", nil];
[eventData setObject:@"Jun 13, 2012 12:00:00 AM" forKey:@"eventDate"];
[eventData setObject:@"hjhj" forKey:@"text"];
.
.
.
NSMutableDictionary *finalDictionary = [NSMutableDictionary dictionaryWithObjectsAndKeys:eventData,@"eventData", nil];
[finalDictionary setObject:@"ELDIARIOMONTANES" forKey:@"type"];
[finalDictionary setObject:@"accIDENTE" forKey:@"title"];

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