使用jq从JSON输出中提取特定字段 [英] Extract a specific field from JSON output using jq

问题描述

我的JSON输出如下:

I have a JSON output as follows:

{
  "example": {
    "sub-example": [
      {
        "name": "123-345",
        "tag" : 100
      },
      {
        "name": "234-456",
        "tag" : 100
      },
      {
        "name": "4a7-a07a5",
        "tag" : 100
      }
    ]
  }
}

我想提取三个名称"字段的值并将其存储在三个变量中.

I want to extract the values of the three "name" fields and store it in three variables.

我尝试过cat json_file | jq '.["example.sub-example.name"]'提取名称"字段的值，但这不起作用.

I tried cat json_file | jq '.["example.sub-example.name"]' to extract the value of the "name" field but that doesn't work.

有人可以告诉我如何使用jq(或其他方法)实现这一目标吗?

Can anyone tell me how to achieve this using jq (or some other method)?

推荐答案

如果只想提取name字段，则要查找的命令是jq '.example."sub-example" | .[] | .name'.如果要将名称保留在数组中，请将整个jq表达式包装在方括号中.

If you just want to extract the name fields, the command you're looking for is jq '.example."sub-example" | .[] | .name'. If you want to keep the names in an array, wrap the whole jq expression in square brackets.

这篇关于使用jq从JSON输出中提取特定字段的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！