以编程方式返回两个json文件之间的差异的最佳方法 [英] Best way of returning differences of two json files programatically

问题描述

我有两个json文件，我想获取一个包含差异的json. 很重要，无论更改某些元素的顺序如何，都只显示内容的实际差异.

I have two json files and I would like to get a json containing the differences. It is important that only the actual differences of content should be shown, regardless of changing the order of some elements.

做到这一点的最佳方法是什么?我正在寻找一种尽可能高效的解决方案，因为json可能包含大量数据，并且用户需要尽快完成工作.

What would be the best way to do that? I am searching for a solution as efficient as possible, since jsons may contain lots of data, and users need jobs to be done as quick as possible.

注意:json可能包含以不同深度编码的数据.任何编程语言都可以，但是我希望可以在php中轻松实现的答案.

Note: The jsons might contain data encoded at different depths. Any programming language is ok, but I would prefer an answer that could easily be implemented in php.

推荐答案

基本上，您想要的是与array_diff_assoc类似的东西，但适用于json对象，并且是递归的.

Basically, what you want is something similar to array_diff_assoc, but applied to json objects, and recursive.

由于引用问题，array_diff函数不是递归的:可以将数组的引用分配给该数组的条目，从而使数组无限递归.我认为使用json对象无法获得相同的情况，从而使递归函数变得安全.

The array_diff functions are not recursive because of reference issues: it is possible to assign a reference of an array to an entry of that array, making the array infinitely recursive. I don't think it is possible to get the same situation with a json object, thus making a recursive function safe.

让我们假设您希望计算对象A和对象B之间的差，并将结果保存在对象C中. 原理是遍历A的每个字段(foreach应该这样做)，以及何时:

Let's suppose that you wish to compute the difference between object A and B, and have the result in object C. The principle is to loop over each field of A (a foreach should do), and when:

• B中没有这样的字段，请通过C复制它.
• B中存在一个相似的字段，将A字段与B字段之差的结果放入C中，这是对以这些字段为参数的diff函数以及结果的新鲜对象的递归调用.

应遵守A的顺序.

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