如何将JSON字符串转换为BSONDocument [英] How to convert JSON String to a BSONDocument
问题描述
我具有以下使用reactmongogo驱动程序的功能,并且实际上在写数据库方面做得很好.
I have the following function that uses the reactivemongo driver and actually does a good job writing to the database.
def writeDocument() = {
val document = BSONDocument(
"firstName" -> "Stephane",
"lastName" -> "Godbillon",
"age" -> 29)
val future = collection.insert(document)
future.onComplete {
case Failure(e) => throw e
case Success(result) => {
println("successfully inserted document with result = " + result)
}
}
}
但是该功能的局限性在于将JSON硬编码到BSONDocument中.如何更改它,以便可以将任何JSON字符串传递给函数?
But the limitation of that function is that the JSON is hardcoded into a BSONDocument. How can I change it so that I can pass any JSON String into the function?
简而言之,问题:如何将JSON字符串转换为BSONDocument?
Question in short: How do I convert a JSON String into a BSONDocument?
更新2:
package controllers
//import play.api.libs.json._
//import reactivemongo.bson._
//import play.api.libs.json.Json
import scala.util.{Success, Failure}
import reactivemongo.api._
//import scala.concurrent.ExecutionContext.Implicits.global
import play.modules.reactivemongo.json.collection._
import reactivemongo.play.json._
object Mongo {
//val collection = connect()
def collection: JSONCollection = {
val driver = new MongoDriver
val connection = driver.connection(List("localhost"))
val db = connection("superman")
db.collection[JSONCollection]("IncomingRequests")
}
// TODO: Make this work with any JSON String
def writeDocument() = {
val jsonString = """{
| "guid": "alkshdlkasjd-ioqweuoiquew-123132",
| "title": "Hello-2016",
| "year": 2016,
| "action": "POST",
| "start": "2016-12-20",
| "stop": "2016-12-30"}"""
val document = Json.parse(jsonString)
val future = collection.insert(document)
future.onComplete {
case Failure(e) => throw e
case Success(result) => {
println("successfully inserted document with result = " + result)
}
}
}
}
现在的问题是import reactivemongo.play.json._
被视为未使用的导入(在我的IntelliJ上),我仍然收到以下错误
The problem now is that import reactivemongo.play.json._
is treated as an unused import (on my IntelliJ) and I still get the following error
[info] Compiling 9 Scala sources and 1 Java source to /Users/superman/target/scala-2.11/classes...
[error] /Users/superman/app/controllers/Mongo.scala:89: No Json serializer as JsObject found for type play.api.libs.json.JsValue. Try to implement an implicit OWrites or OFormat for this type.
[error] Error occurred in an application involving default arguments.
[error] val future = collection.insert(document)
[error] ^
[error] one error found
[error] (compile:compileIncremental) Compilation failed
[error] application -
! @6oo00g47n - Internal server error, for (POST) [/validateJson] ->
play.sbt.PlayExceptions$CompilationException: Compilation error[No Json serializer as JsObject found for type play.api.libs.json.JsValue. Try to implement an implicit OWrites or OFormat for this type.
Error occurred in an application involving default arguments.]
at play.sbt.PlayExceptions$CompilationException$.apply(PlayExceptions.scala:27) ~[na:na]
at play.sbt.PlayExceptions$CompilationException$.apply(PlayExceptions.scala:27) ~[na:na]
at scala.Option.map(Option.scala:145) ~[scala-library-2.11.6.jar:na]
at play.sbt.run.PlayReload$$anonfun$taskFailureHandler$1.apply(PlayReload.scala:49) ~[na:na]
at play.sbt.run.PlayReload$$anonfun$taskFailureHandler$1.apply(PlayReload.scala:44) ~[na:na]
at scala.Option.map(Option.scala:145) ~[scala-library-2.11.6.jar:na]
at play.sbt.run.PlayReload$.taskFailureHandler(PlayReload.scala:44) ~[na:na]
at play.sbt.run.PlayReload$.compileFailure(PlayReload.scala:40) ~[na:na]
at play.sbt.run.PlayReload$$anonfun$compile$1.apply(PlayReload.scala:17) ~[na:na]
at play.sbt.run.PlayReload$$anonfun$compile$1.apply(PlayReload.scala:17) ~[na:na]
推荐答案
首先,您可以使用reactmongo将模型类序列化为BSON.查看文档以了解操作方法.
First, you could serialize your model classes as BSON using reactivemongo. Check docs to see how.
如果您想通过play json在String
中制作BSONDocument
,则可以使用
If you want to make a BSONDocument
from String
through play json you can use
val playJson: JsValue = Json.parse(jsonString)
val bson: BSONDocument = play.modules.reactivemongo.json.BSONFormats.reads(playJson).get
修改
我在这里的文档中发现了更多信息:
I found more in the docs here:
http://reactivemongo.org/releases/0.11/documentation/tutorial/play2.html
您可以导入这两个
import reactivemongo.play.json._
import play.modules.reactivemongo.json.collection._
而不是使用默认的Collection实现(该实现与 BSON结构+ BSONReader/BSONWriter),我们使用专门的 与JsObject +读/写一起使用的实现.
Instead of using the default Collection implementation (which interacts with BSON structures + BSONReader/BSONWriter), we use a specialized implementation that works with JsObject + Reads/Writes.
因此,您可以像这样创建专门的集合(必须为def
,而不是val
):
So you create specialized collection like this (must be def
, not val
):
def collection: JSONCollection = db.collection[JSONCollection]("persons")
,从现在开始,您可以将其与play json一起使用,而不是与BSON一起使用,因此只需将Json.parse(jsonString)
作为要插入的文档传递就可以了.您可以在链接中看到更多示例.
and from now on you can use it with play json, instead of BSON, so simply passing in Json.parse(jsonString)
as a document to insert should work. You can see more examples in the link.
编辑2 我让您的代码可以编译:
Edit 2 I got your code to compile:
程序包控制器
import play.api.libs.concurrent.Execution.Implicits._
import play.api.libs.json._
import play.modules.reactivemongo.json.collection.{JSONCollection, _}
import reactivemongo.api.MongoDriver
import reactivemongo.play.json._
import play.api.libs.json.Reads._
import scala.util.{Failure, Success}
object Mongo {
def collection: JSONCollection = {
val driver = new MongoDriver
val connection = driver.connection(List("localhost"))
val db = connection("superman")
db.collection[JSONCollection]("IncomingRequests")
}
def writeDocument() = {
val jsonString = """{
| "guid": "alkshdlkasjd-ioqweuoiquew-123132",
| "title": "Hello-2016",
| "year": 2016,
| "action": "POST",
| "start": "2016-12-20",
| "stop": "2016-12-30"}"""
val document = Json.parse(jsonString).as[JsObject]
val future = collection.insert(document)
future.onComplete {
case Failure(e) => throw e
case Success(result) =>
println("successfully inserted document with result = " + result)
}
}
}
重要的进口是
import play.api.libs.json.Reads._
,您需要的是JsObject
,而不仅仅是任何JsValue
and you need JsObject
, not just any JsValue
val document = Json.parse(jsonString).as[JsObject]
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