JSONObject文本必须在1 [字符2第1行]处以'{'开头,错误为'{' [英] A JSONObject text must begin with '{' at 1 [character 2 line 1] with '{' error

查看:196
本文介绍了JSONObject文本必须在1 [字符2第1行]处以'{'开头,错误为'{'的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

String JSON = "http://www.json-generator.com/j/cglqaRcMSW?indent=4";

JSONObject jsonObject = new JSONObject(JSON);
JSONObject getSth = jsonObject.getJSONObject("get");
Object level = getSth.get("2");

System.out.println(level);

我提到了许多解析此链接的解决方案,同样的问题. 有谁能给我一个解析它的简单解决方案.

I referred many solutions for parsing this link, still getting the same error in question. Can any give me a simple solution for parsing it.

推荐答案

您的问题是String JSON = "http://www.json-generator.com/j/cglqaRcMSW?indent=4";不是JSON.
您想要做的是打开一个与" http://www的HTTP连接. .json-generator.com/j/cglqaRcMSW?indent = 4 ",然后解析JSON 响应.

Your problem is that String JSON = "http://www.json-generator.com/j/cglqaRcMSW?indent=4"; is not JSON.
What you want to do is open an HTTP connection to "http://www.json-generator.com/j/cglqaRcMSW?indent=4" and parse the JSON response.

String JSON = "http://www.json-generator.com/j/cglqaRcMSW?indent=4";
JSONObject jsonObject = new JSONObject(JSON); // <-- Problem here!

将不会打开与站点的连接并检索内容.

Will not open a connection to the site and retrieve the content.

这篇关于JSONObject文本必须在1 [字符2第1行]处以'{'开头,错误为'{'的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆