如何使用jQuery从JSON获取属性值 [英] How to get values of attributes from JSON using jQuery

问题描述

我正在使用Newtonsoft dll从xml文件生成json.从下面如何将地址详细信息放入列表(如果示例中还有更多信息)并将其写到下拉列表中，则我具有以下有效的json(已选中onjsonlint):

I am generating json from an xml file using the Newtonsoft dll. From the below how would I get the address details into a list(if there were more in the example) and write them to a dropdown list I have the following valid json (checked onjsonlint):

{
    "?xml": {
        "@version": "1.0",
        "@encoding": "utf-8"
    },
    "Root": {
        "Information": {
            "Error": {
                "ErrorNo": "0",
                "ErrorMsg": null
            },
            "Address": {
                "Address": [
                    {
                        "@AddressID": "14961943",
                        "@Sequence": "1",
                        "@Description": "Some Company Name, Some Building, 10 Some Street, Some County, Some City"
                    }            
                ]
            }
        }
    }
}

推荐答案

尝试一下:

var json = // that object above
var addresses = json.Root.Information.Address.Address;

for (var i = 0; i < addresses.length; i++) {
    var $option = $("<option></option>").val(addresses[i]["@AddressID"]).text(addresses[i]["@Description"]);
    $("#mySelect").append($option);
}

小提琴示例

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