使用Retrofit解析动态未知命名数组Json [英] Parse Dynamic unknown named array Json using Retrofit
本文介绍了使用Retrofit解析动态未知命名数组Json的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我是新手，下面是json
i'm new to retrofit,below is the json
{
"response": "success",
"servicecode": "134",
"forecast": {
"month": {
"jan": [
{
"id": "1",
"price": "12",
"Product": "1086",
"Qty": "14",
"date": "2018-10-27 16:08:57"
},
{
"id": "2",
"price": "19",
"Product": "1746",
"Qty": "45",
"date": "2018-10-27 16:08:57"
}
],
"april": [
{
"id": "3",
"price": "89",
"Product": "1986",
"Qty": "15",
"date": "2018-10-27 16:08:57"
},
{
"id": "1",
"price": "12",
"Product": "1086",
"Qty": "145",
"date": "2018-10-27 16:08:57"
}
],
"jun": [
{
"id": "81",
"price": "132",
"Product": "17086",
"Qty": "1445",
"date": "2018-10-27 16:08:57"
},
{
"id": "11",
"price": "132",
"Product": "10786",
"Qty": "1445",
"date": "2018-10-27 16:08:57"
}
]
}
},
"message": "Competitor Sales."
}
在这里，那些月份(1月，4月，6月)是动态的(可能会到来，或者不会)，因此如何使用改型来解析它. 我不知道如何创建我的模型类. 我的问题看起来像是这，但是没有更多了细节. 告诉我一个更好的教程.
here, those months(jan, april, jun) are dynamic(they may come or they won't) so how to parse this using retrofit. i have no idea how to create my model class. my issue some what looks like this,but in that there's no more details. tell me a better tutorial for this.
下面的模型类
class ForecastViewModel {
@SerializedName("forecast")
Forecast[] data;
public Forecast[] getData() { return data; }
private class Forecast {
@SerializedName("month")
MonthData[] month;
public MonthData[] getMonth() { return month; }
private class MonthData {
private Map<String, Pojo> forecastdata = new HashMap<>();
private class Pojo {
@SerializedName("id")
@Expose
private String pID;
@SerializedName("price")
@Expose
private String pPrice;
@SerializedName("Product")
@Expose
private String pProduct;
@SerializedName("Qty")
@Expose
private String pQty;
@SerializedName("date")
@Expose
private String pDate;
public String getpID() {
return pID;
}
public void setpID(String pID) {
this.pID = pID;
}
public String getpPrice() {
return pPrice;
}
public void setpPrice(String pPrice) {
this.pPrice = pPrice;
}
public String getpProduct() {
return pProduct;
}
public void setpProduct(String pProduct) {
this.pProduct = pProduct;
}
public String getpQty() {
return pQty;
}
public void setpQty(String pQty) {
this.pQty = pQty;
}
public String getpDate() {
return pDate;
}
public void setpDate(String pDate) {
this.pDate = pDate;
}
}
}
}
}
... !!
推荐答案
method 1 - without using model class
method 1 - without using model class
假设您的"month"对象是jsonObjectResponse.您可以使用Iterator
Suppose your "month" object is jsonObjectResponse.You can make use of Iterator
JSONObject jsonResponse = new JSONObject(jsonObjectResponse);
Iterator iteratorObj = jsonResponse.keys();
while (iteratorObj.hasNext())
{
JSONArray monthArray=(JSONArray)iteratorObj.next()
//add all monthArray to an arraylist
}
**为模型类编辑**
** Edit for model class **
method 2 - using model class
method 2 - using model class
您可以使用Map<String, List<MonthModel>>从month获得动态响应
You can use Map<String, List<MonthModel>> to get dynamic response from month
您有两个创建三个模型分类，如下所示:
You have two create three model clases like this:
Example.java
public class Example {
@SerializedName("response")
@Expose
private String response;
@SerializedName("servicecode")
@Expose
private String servicecode;
@SerializedName("forecast")
@Expose
private Forecast forecast;
@SerializedName("message")
@Expose
private String message;
public String getResponse() {
return response;
}
public void setResponse(String response) {
this.response = response;
}
public String getServicecode() {
return servicecode;
}
public void setServicecode(String servicecode) {
this.servicecode = servicecode;
}
public Forecast getForecast() {
return forecast;
}
public void setForecast(Forecast forecast) {
this.forecast = forecast;
}
public String getMessage() {
return message;
}
public void setMessage(String message) {
this.message = message;
}
}
Forecast.java
public class Forecast {
@SerializedName("month")
@Expose
private Map<String, List<MonthModel>> result;
public Map<String, List<MonthModel>> getResult() {
return result;
}
public void setResult(Map<String, List<MonthModel>> result) {
this.result = result;
}
}
MonthModel.java
public class MonthModel {
@SerializedName("id")
@Expose
private String id;
@SerializedName("price")
@Expose
private String price;
@SerializedName("Product")
@Expose
private String product;
@SerializedName("Qty")
@Expose
private String qty;
@SerializedName("date")
@Expose
private String date;
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getPrice() {
return price;
}
public void setPrice(String price) {
this.price = price;
}
public String getProduct() {
return product;
}
public void setProduct(String product) {
this.product = product;
}
public String getQty() {
return qty;
}
public void setQty(String qty) {
this.qty = qty;
}
public String getDate() {
return date;
}
public void setDate(String date) {
this.date = date;
}
}
现在执行如下所示的改装呼叫
Now perform retrofit call like the following
private void getMonthData() {
Gson gson = new GsonBuilder()
.setLenient()
.create();
Retrofit retrofit = new Retrofit.Builder()
.addConverterFactory(GsonConverterFactory.create(gson))
.baseUrl("add_base_url")
.build();
RequestInterface requestInterface = retrofit.create(RequestInterface.class);
Call<Example> call = requestInterface.getMonths();
call.enqueue(new Callback<Example>() {
@Override
public void onResponse(Call<Example> call, Response<Example> response) {
Map<String, List<MonthModel>> resultMap=response.body().getForecast().getResult();
Toast.makeText(MainActivity.this, "Success", Toast.LENGTH_SHORT).show();
}
@Override
public void onFailure(Call<Example> call, Throwable t) {
Toast.makeText(MainActivity.this, "Failure", Toast.LENGTH_SHORT).show();
}
});
}
RequestInterface.java
public interface RequestInterface {
@GET("add_your_url_endpoint")
Call<Example> getMonths();
}
这篇关于使用Retrofit解析动态未知命名数组Json的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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