PHP获取JSON POST数据 [英] PHP Get JSON POST Data

问题描述

我已经设置了一个Webhook来将通知发布到服务器上的PHP页面.到我服务器的通知请求是这样的:

I've setup a Webhook to get notifications posted to a PHP page on my server. The notification request to my server is like this:

POST /message/receive HTTP/1.1
Host: http://www.yoururl.com/zipwhip/api/receive
Content-Length: 581
Content-Type: application/json; charset=UTF-8

{ "body":"Thanks for texting, this is an auto reply!",
  "bodySize":42,
  "visible":true,
  "hasAttachment":false,
  "dateRead":null,
  "bcc":null,
  "finalDestination":"4257772300",
  "messageType":"MO",
  "deleted":false,
"statusCode":4,
"id":634151298329219072, "scheduledDate":null, "fingerprint":"132131532", "messageTransport":9, "contactId":3382213402, "address":"ptn:/4257772222",
"read" "dateCreated":"2015-08-19T16:53:45-07:00", "dateDeleted":null,
  "dateDelivered":null,
  "cc":null,
  "finalSource":"4257772222",
} "dev

我尝试使用以下内容将JSON数据转换为可以使用的字符串，但到目前为止我什么都没得到:

I've tried using the following to convert the JSON data to a string that I can work with, but I'm getting nothing so far:

$inputJSON = file_get_contents('php://input');
$input= json_decode( $inputJSON, TRUE ); 

我读过的所有内容都表明该方法有效-我测试了以下内容，并且该方法确实有效:

Everything I've read indicates this should work - I tested the following and this is actually working:

$webhookContent = "";

    $webhook = fopen('php://input' , 'rb');
    while (!feof($webhook)) {
        $webhookContent .= fread($webhook, 4096);
    }
    fclose($webhook);

我试图了解为什么file_get_contents('php://input');当我阅读的所有内容都表明我应该使用的功能以及为什么使用fopen('php://input'，'rb')时，该功能不起作用.可以代替吗?

I'm trying to understand why file_get_contents('php://input'); doesn't work when everything I've read indicates that's the function I should be using, and why fopen('php://input' , 'rb'); works instead?

如果我执行var_dump($ inputJSON)，我会得到:

If I do var_dump($inputJSON) I get:

    string(527) "{ "body":"Thanks for texting, this is an auto reply!",
  "bodySize":42,
  "visible":true,
  "hasAttachment":false,
  "dateRead":null,
  "bcc":null,
  "finalDestination":"4257772300",
  "messageType":"MO",
  "deleted":false,
"statusCode":4,
"id":634151298329219072, "scheduledDate":null, "fingerprint":"132131532", "messageTransport":9, "contactId":3382213402, "address":"ptn:/4257772222",
"read" "dateCreated":"2015-08-19T16:53:45-07:00", "dateDeleted":null,
  "dateDelivered":null,
  "cc":null,
  "finalSource":"4257772222",
}"

var_dump($ input)返回NULL

var_dump($input) returns NULL

推荐答案

以下内容现在对我有用:

The following is working for me now:

$inputJSON = file_get_contents('php://input');
$input= json_decode( $inputJSON ); 

我认为我的问题正在使用:

I think my issue was using:

$input= json_decode( $inputJSON, TRUE ); 

而不只是:

$input= json_decode( $inputJSON ); 

这篇关于PHP获取JSON POST数据的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！