JSON数据转换为Django模型 [英] JSON data convert to the django model

问题描述

我需要将JSON数据转换为Django模型.

I need to convert JSON data to django model.

这是我的JSON数据

{
  "data": [
    {
      "id": "20ad5d9c-b32e-4599-8866-a3aaa5ac77de",
      "name": "name_1"
    },
    {
      "id": "7b6d76cc-86cd-40f8-be90-af6ced7fec44",
      "name": "name_2"
    },
    {
      "id": "b8843b1a-9eb0-499f-ba64-25e436f04c4b",
      "name": "name_3"
    }
  ]
}

这是我的django方法

This is my django method

def get_titles():
    url = 'http://localhost:8080/titles/' 
    r = requests.get(url)
    titles = r.json()
    print(titles['data'])

我需要的是转换为模型并传递给模板.请让我知道如何将JSON转换为模型.

What I need is convert to the model and pass to the template. Please let me know how to convert JSON to Model.

推荐答案

在Django模板中使用JSON

您不必将JSON结构转换为Django模型，仅在Django模板中使用它:JSON结构(Python dict)在Django模板中就可以正常工作

Using JSON in Django templates

You don't have to convert the JSON structure into a Django model just to use it in a Django template: JSON structures (Python dicts) work just fine in a Django template

例如如果将{'titles': titles['data']}作为上下文传递到模板，则可以将其用作:

e.g. if you pass in {'titles': titles['data']} as the context to your template, you can use it as:

{% for title in titles %}
    ID is {{title.id}}, and name is {{title.name}}
{% endfor %}

只要您不需要使用Django存储数据，上述解决方案就可以正常工作.如果要存储，请阅读以下内容.

As long as you don't need to store the data with Django, the above solution works just fine. If you want to store, read below.

您可以创建一个模型来存储JSON数据.存储后，您可以将查询集传递给模板

You can create a model to store that JSON data in. Once stored you can pass the queryset to your template

class Title(models.Model)
    id = models.CharField(max_length=36)
    name = models.CharField(max_length=255)

或使用UUIDField

class Title(models.Model)
    id = models.UUIDField(primary_key=True)
    name = models.CharField(max_length=255)

将数据存储在Django模型中

# Read the JSON
titles = r.json()
# Create a Django model object for each object in the JSON 
for title in titles['data']:
    Title.objects.create(id=title['id'], name=title['name'])

使用存储的数据作为模板上下文传递

# Then pass this dict below as the template context
context = {'titles': Title.objects.all()}

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