根据.Net(C#)中的字段反序列化json [英] Deserialize json based on fields in .Net (C#)
问题描述
我正在编写一个应用程序,该应用程序获得这样的对象的Json
列表:
I'm writing an app that gets a Json
list of objects like this:
[
{
"ObjectType": "apple",
"ObjectSize": 35,
"ObjectCost": 4,
"ObjectTaste": "good",
"ObjectColor": "golden"
},
{
"ObjectType": "books",
"ObjectSize": 53,
"ObjectCost": 7,
"Pages": 100
},
{
"ObjectType": "melon",
"ObjectSize": 35,
"ObjectTaste": "good",
"ObjectCost": 5
},
{
"ObjectType": "apple",
"ObjectSize": 29,
"ObjectCost": 8,
"ObjectTaste": "almost good",
"ObjectColor": "red"
}
]
我想创建一个基类ItemToSell
(大小,成本),并从中派生Apple,Melon和Book,然后根据"ObjectType
"字段对它适合的任何类进行反序列化.我希望它建立一个ItemToSell
对象的列表,每个对象都是Apple,Melon或Book.
I want to make a base class ItemToSell
(size,cost), and derive Apple, Melon and Book from it, then make the deserialization based on the "ObjectType
" field to whatever class it fits. I want it to build a list of ItemToSell
objects, every object being Apple, Melon or Book.
如何在.Net中做到这一点?
How could I do this in .Net?
先谢谢您了:)
我知道如何在Big类及其包含的所有字段中反序列化它,例如:Base(ObjectType,ObjectSize,ObjectCost,ObjectColor,Pages)
.但是我希望它通过ObjectType
区分类,因此我不会有任何有用的字段,例如每本书的Pages字段或每本书的ObjectTaste
.
I know how to deserialize it in a Big class with all the fields it can ever contain, like: Base(ObjectType,ObjectSize,ObjectCost,ObjectColor,Pages)
. But I want it to distinguish between classes by the ObjectType
so I won't have any usefulness fields like Pages field for every book item or ObjectTaste
for every book.
推荐答案
前段时间,我遇到了同样的问题.
Some time ago I had the same problem.
您将可以使用Json.NET,但是如果您无法控制json文档(例如:它已被其他框架序列化"),则需要创建一个自定义JsonConverter,如下所示:
You'll can use Json.NET, but if you don't have control over the json document (as in: 'it has been serialized by some other framework') you'll need to create a custom JsonConverter like this:
class MyItemConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return typeof(ItemToSell).IsAssignableFrom(objectType);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
JObject obj = JObject.Load(reader);
string discriminator = (string)obj["ObjectType"];
ItemToSell item;
switch (discriminator)
{
case "apple":
item = new Apple();
break;
case "books":
item = new Books();
break;
case "melon":
item = new Melon();
break;
default:
throw new NotImplementedException();
}
serializer.Populate(obj.CreateReader(), item);
return item;
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
}
}
然后,您需要将其添加到JsonSerializerSettings的转换器中,如下所示:
Then you'll need to add it to the converters of the JsonSerializerSettings like so:
JsonSerializerSettings settings = new JsonSerializerSettings
{
TypeNameHandling = TypeNameHandling.Objects,
};
settings.Converters.Add(new MyItemConverter());
var items = JsonConvert.DeserializeObject<List<ItemToSell>>(response, settings);
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