从Wikipedia API提取数据 [英] Extracting data from Wikipedia API

问题描述

我希望能够使用json从Wikipedia中提取标题和描述.所以...维基百科不是我的问题，我是json的新手，并且想知道如何使用它.现在我知道有成百上千的教程，但是我已经工作了几个小时，它什么也没显示，这是我的代码:

I would like to be able to extract a title and description from Wikipedia using json. So... wikipedia isn't my problem, I'm new to json and would like to know how to use it. Now I know there are hundreds of tutorials, but I've been working for hours and it just doesn't display anything, heres my code:

<?php
  $url="http://en.wikipedia.org/w/api.php?action=query&prop=extracts|info&exintro&titles=google&format=json&explaintext&redirects&inprop=url";

    $json = file_get_contents($url);
    $data = json_decode($json, TRUE);

    $pageid = $data->query->pageids;
    echo $data->query->pages->$pageid->title;
?>

只需单击它即可更轻松:

Just so it easier to click:

• 我知道我可能做错了一点小事，但是它确实困扰着我，还有代码……我习惯于使用xml，并且我已经做了很多切换，所以您可以解释一下这对我和未来的访问者来说有点麻烦，因为我很困惑……您需要我没说的任何东西，只需评论一下，确定可以得到，谢谢，谢谢！

  I know I've probably just done a tiny thing wrong, but its really bugging me, and the code... I'm used to using xml, and I have pretty much just made the switch, so can you explain it a bit for me and for future visitors, because I'm very confused... Anything you need that I haven't said, just comment it, im sure I can get it, and thanks, in advance!

  推荐答案

  $pageid返回带有一个元素的数组.如果您只想握拳，那您应该这样做:

  $pageid was returning an array with one element. If you only want to get the fist one, you should do this:

  $pageid = $data->query->pageids[0];
  

  您可能会收到以下警告:

  You were probably getting this warning:

   Array to string conversion 
  

  完整代码:

      $url = 'http://en.wikipedia.org/w/api.php?action=query&prop=extracts|info&exintro&titles=google&format=json&explaintext&redirects&inprop=url&indexpageids';
  
      $json = file_get_contents($url);
      $data = json_decode($json);
  
      $pageid = $data->query->pageids[0];
      echo $data->query->pages->$pageid->title;
  

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