如何将jSON转换为XML [英] How do I Convert jSON to XML
本文介绍了如何将jSON转换为XML的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在我开始之前,我知道有很多与此类似的问题,但是请相信我,我阅读了全部(即使不是大多数).我尝试了很多解决方案,但似乎都没有用.我得到的结果是一棵空白的树".这是我正在使用的代码.
Before I begin, I know there are a bunch of questions similar to this, but trust me, I read all, if not most of them. I tried a bunch of solutions, but none of them seem to work. I'm getting a blank "tree" as my result. Here is the code that I am using.
$jSON = json_decode('array here');
function array2xml($array, $xml = false){
if($xml === false){
$xml = new SimpleXMLElement('<result/>');
}
foreach($array as $key => $value){
if(is_array($value)){
array2xml($value, $xml->addChild($key));
} else {
$xml->addChild($key, $value);
}
}
return $xml->asXML();
}
这是我正在使用的jSON数组.
Here is the jSON array that I'm using.
我不确定为什么它不起作用.这是我使用该功能时的结果.
I'm not sure why it isn't working. Here is the result when I use that function.
<result>
<generated_in>155ms</generated_in>
</result>
推荐答案
与其给函数提供对象,不如给它提供数组:
Instead of feeding your function an object, try to feed an array instead:
$jSON = json_decode($raw_data, true);
// ^ add second parameter flag `true`
示例:
function array2xml($array, $xml = false){
if($xml === false){
$xml = new SimpleXMLElement('<result/>');
}
foreach($array as $key => $value){
if(is_array($value)){
array2xml($value, $xml->addChild($key));
} else {
$xml->addChild($key, $value);
}
}
return $xml->asXML();
}
$raw_data = file_get_contents('http://pastebin.com/raw.php?i=pN3QwSHU');
$jSON = json_decode($raw_data, true);
$xml = array2xml($jSON, false);
echo '<pre>';
print_r($xml);
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