在android应用中使用POST将JSON发送到服务器 [英] sending JSON to server using POST in android app
问题描述
我正在创建一个Android应用，以将JSON发送到服务器端php脚本并将其存储在数据库中
I'm creating an android app to send JSON to a server-side php script and store it in a database
这是应用程序中的相关代码
Here's the relevant code from the app
public String POST(){
String url = "http://192.168.150.1/t2.php";
InputStream inputStream = null;
String result = "";
try {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
String json = "";
JSONObject jsonObject = new JSONObject();
jsonObject.put("str", "bang");
jsonObject.put("lat", 3.10);
jsonObject.put("lon", 3.10);
json = jsonObject.toString();
Toast.makeText(this, json, Toast.LENGTH_LONG).show();
StringEntity se = new StringEntity(json);
httpPost.setEntity(se);
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
HttpResponse httpResponse = httpclient.execute(httpPost);
inputStream = httpResponse.getEntity().getContent();
if(inputStream != null)
result = "success";
else
result = "Did not work!";
} catch (Exception e) {
Log.d("InputStream", e.getLocalizedMessage());
}
return result;
}
这是php脚本
<?php
$connection = mysql_connect("192.168.150.1","****","****");
if (!$connection) {
die("Database connection failed: " . mysql_error());
}
echo "connection success\n";
$db_select = mysql_select_db("ps1",$connection);
if (!$db_select) {
die("Database selection failed: " . mysql_error());
}
echo "db selections success";
?>
<html>
<head>
<title> hl</title>
</head>
<body>
<p>hello</p>
<?php
$js = json_decode(file_get_contents('php://input'));
//$js = json_decode($_POST); ------------ ******
$atr ='';
$val = '';
foreach ($js as $a => $v)
{
$atr = $atr.','.$a;
$val = $val.','.$v;
}
$atr = ltrim($atr,',');
$val = ltrim($val,',');
echo "insert into js (".$atr.") values (" .$val . ");";
$result = mysql_query("insert into js (".$atr.") values (" .$val . ");", $connection);
if (!$result) {
die("Database query failed: " . mysql_error());
}
?>
</body>
</html>
<?php
mysql_close($connection);
?>
现在，如果尝试从应用程序的对象发送JSON，则什么都不会发生
Now if try to send a JSON from object from the app, nothing happens
但如果我尝试
curl -H内容类型:application/json" -d'{"str":"\" hello \"，"lat":"3.1"，"lon":"5.2"}'localhost/t2.php
curl -H "Content-Type: application/json" -d '{"str":"\"hello\"","lat":"3.1","lon":"5.2"}' localhost/t2.php
在命令行中有效.
如果我尝试取消注释$ js = json_decode($ _ POST);在PHP脚本中插入一行，并注释掉php://input行，然后不传输JSON对象，而是将值"，0,0插入数据库中
Also if I try to uncomment the $js = json_decode($_POST); line in the PHP script and comment out the php://input line, then the JSON object is not transferred but the values "", 0,0 are inserted into the database
I think there must be an error with the app code.I'm following the tutorial and code from here http://hmkcode.com/android-send-json-data-to-server/
问题
- 有人可以解释我做错了什么和可行的解决方案吗?
- php://input和$ _POST有什么区别?
谢谢
查询
推荐答案
使用此方法发出POST请求:
Use this method to make POST Request :
public String makePOSTRequest(String url, List<NameValuePair> nameValuePairs) {
String response = "";
try {
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
response = EntityUtils.toString(httpEntity);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
Log.d(LOGTAG, "POST Response >>> " + response);
return response;
}
用法:
在Java中:
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("json",jsonObject.toString()));
String response = makePOSTRequest(String url, nameValuePairs );
服务器端PHP:
$jsonInput = $_POST['json'];
json_decode($jsonInput);
这篇关于在android应用中使用POST将JSON发送到服务器的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
