从JSON字符串中删除双引号 [英] Removing Double Quotes from JSON String
本文介绍了从JSON字符串中删除双引号的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我正在获取一个看起来像这样的xml文件
I am taking an xml file that looks like this
<FCDMC><rpt_info created="data generated 04/16/2013 16:45"/><gage_rain id="770" last_rpt="2013-04-16T14:22:11" min_10="0.00" min_30="0.00" hour_1="0.00" hour_3="0.00" hour_6="0.00" day_1="0.00" day_3="0.00" day_7="0.00" name="Tat Momolikot Dam" lat="032:39:04" long="111:55:41"/></FCDMC>
使用此xsl样式表来更改/修改xml文档.
Using this xsl style sheet to change/modify the xml document.
<xsl:stylesheet version="1.0">
<xsl:output method="xml" encoding="utf-8" media-type="text/xml" indent="yes"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="rpt_info">
<xsl:element name="meta" select=".">
<xsl:for-each select="@created">
<xsl:element name="created" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="gage_rain">
<xsl:element name="data" select=".">
<xsl:for-each select="@id">
<xsl:element name="site" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
<xsl:for-each select="@lat">
<xsl:element name="latitude" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
<xsl:for-each select="@long">
<xsl:element name="longitude" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
<xsl:for-each select="@name">
<xsl:element name="name" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
<xsl:for-each select="@last_rpt">
<xsl:element name="last_rpt" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
<xsl:for-each select="@min_10">
<xsl:element name="rain" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
<xsl:for-each select="@min_30">
<xsl:element name="rain" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
<xsl:for-each select="@hour_1">
<xsl:element name="rain" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
<xsl:for-each select="@hour_3">
<xsl:element name="rain" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
<xsl:for-each select="@hour_6">
<xsl:element name="rain" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
<xsl:for-each select="@day_1">
<xsl:element name="rain" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
<xsl:for-each select="@day_3">
<xsl:element name="rain" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
<xsl:for-each select="@day_7">
<xsl:element name="rain" select=".">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
比起我使用PHP输出新的xml文件
Than I am using PHP to output the new xml file
<?php
header('Content-Type: application/xml');
$xml = new DOMDocument;
$xml->load('http://alert.fcd.maricopa.gov/alert/Google/xml/fcdmc_alert_rain.xml');
$xsl = new DOMDocument;
$xsl->load('http://alert.fcd.maricopa.gov/alert/Google/v3/xslt/fcdmc_alert_rain.xsl');
$proc = new XSLTProcessor;
$proc->importStyleSheet($xsl);
echo $proc->transformToXML($xml);
?>
和此php输出JSON
and this php to output JSON
<?php
$xml = simplexml_load_file('http://alert.fcd.maricopa.gov/alert/Google/v3/php/rainfall_data.php');
$json = json_encode($xml);
echo $json;
?>
这是我当前的JSON输出
{"meta":{"created":"04-18-2013 12:45"},"data":[{"site":"770","latitude":"032:39:04","longitude":"111:55:41","name":"Tat Momolikot Dam","last_rpt":"2013-04-18T11:22:11","rain":["0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00"]}]}
这就是我需要JSON输出的样子.我需要删除0.00值附近的双引号(").
{"meta":{"created":"04-18-2013 12:45"},"data":[{"site":"770","latitude":"032:39:04","longitude":"111:55:41","name":"Tat Momolikot Dam","last_rpt":"2013-04-18T11:22:11","rain":[0.00,0.00,0.00,0.00,0.00,0.00,0.00,0.00]}]}
如何更改"rain":[string]?
How do I change the "rain":[string]?
我可以在xsl中执行此操作吗?在PHP中?谢谢.
Do I do it in xsl? In php? Thank you.
推荐答案
从php 5.3.3开始，您可以将JSON_NUMERIC_CHECK标志传递给 json_encode ，它将检查值是否为数字，并使用数字而不是字符串对json字符串进行编码.
As of php 5.3.3 you can pass a JSON_NUMERIC_CHECK flag to json_encode that will check if a value is numeric and encode the json string with a number instead of a string.
根据我的最后一条评论，使用字符串替换，这将起作用:
Per my last comment, using string replace, this would work:
<?php
//the json data, since I don't have the original data, I am just decoding the json output.
$json = '{"meta":{"created":"04-18-2013 12:45"},"data":[{"site":"770","latitude":"032:39:04","longitude":"111:55:41","name":"Tat Momolikot Dam","last_rpt":"2013-04-18T11:22:11","rain":["0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00"]}]}';
//decode the json output
$array = json_decode($json, 1);
//an empty array for rain data
$rain = array();
//loop through each data
foreach($array['data'] as $k=>$v){
//save the rain data
$rain[$k] = $v['rain'];
//overwrite the rain data with a simple unique string that can be replaced
$array['data'][$k]['rain'] = "{rain data {$k}}";
}
//encode the new data with the replacement string
$json = json_encode($array);
//loop over the rain data replacing the rain data replacement string with a JSON_NUMERIC_CHECK json_encoded rain data
foreach($rain as $k=>$v){
//build the search string
$search = '"{rain data '.$k.'}"';
//build the replace string
$replace = json_encode($v, JSON_NUMERIC_CHECK);
//do the replace
$json = str_replace($search, $replace, $json);
}
var_dump($json);
http://codepad.viper-7.com/hiWxjH
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