如何使用php在json中转换mysql数据库表数据 [英] How to convert mysql data base table data in json using php

问题描述

如何使用PHP将MySQL数据库表转换为JSON数据.有什么办法吗?

How to convert MySQL data base table into JSON data using PHP. Is there any way to do this?

以下是我正在使用的php代码:

Below is the php code I am using:

<?php 
$host = "emriphone.db.6420177.hostedresource.com"; 
$user = "emriphone"; 
$pass = "Light12-"; 
$database = "emriphone"; 

$linkID = mysql_connect($host, $user, $pass) or die("Could not connect to host."); 
mysql_select_db($database, $linkID) or die("Could not find database."); 

$sth = mysql_query("SELECT * FROM ProviderAppointmentListings");
$rows = array();
while($r = mysql_fetch_assoc($sth)) {
   $rows[] = $r;
}
print json_encode($rows);
?>

推荐答案

尝试如下:

$query = mysql_query("SELECT * FROM table");
$rows = array();
while($row = mysql_fetch_assoc($query)) {
    $rows[] = $row;
}
print json_encode($rows);

如果您没有json_encode，请在上面的代码之前添加它:

If you don't have json_encode add this before the code above:

if (!function_exists('json_encode'))
{
  function json_encode($a=false)
  {
    if (is_null($a)) return 'null';
    if ($a === false) return 'false';
    if ($a === true) return 'true';
    if (is_scalar($a))
    {
      if (is_float($a))
      {
        // Always use "." for floats.
        return floatval(str_replace(",", ".", strval($a)));
      }

      if (is_string($a))
      {
        static $jsonReplaces = array(array("\\", "/", "\n", "\t", "\r", "\b", "\f", '"'), array('\\\\', '\\/', '\\n', '\\t', '\\r', '\\b', '\\f', '\"'));
        return '"' . str_replace($jsonReplaces[0], $jsonReplaces[1], $a) . '"';
      }
      else
        return $a;
    }
    $isList = true;
    for ($i = 0, reset($a); $i < count($a); $i++, next($a))
    {
      if (key($a) !== $i)
      {
        $isList = false;
        break;
      }
    }
    $result = array();
    if ($isList)
    {
      foreach ($a as $v) $result[] = json_encode($v);
      return '[' . join(',', $result) . ']';
    }
    else
    {
      foreach ($a as $k => $v) $result[] = json_encode($k).':'.json_encode($v);
      return '{' . join(',', $result) . '}';
    }
  }
}

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