将JSON解组到映射/字符串列表 [英] Unmarshal JSON to Map/List of Strings

问题描述

我想将Json解组到字符串的映射/列表(例如Map> ...)

I would like to unmarshal a Json to a Map/List of Strings (eg Map>...)

这是我的输入内容:

{"pointsOfSale": 
{"pointOfSale":[ 
{"href":"\/pointsOfSale\/UUID.0abc2aca-7930-4c9e-9f38-8af3d0692e04", 
"model":{"href":"\/models\/modelePointOfSale", 
"modelType":{"href":"\/modelTypes\/pointOfSale"}}, 
"source":{"href":"\/sources\/TEST"}, 
"attribute":[ 
{"code":"pointOfSalePhysical","value":true}, 
{"code":"mail","value":"Mail1"}, 
{"code":"adresse","value":"address1"}]}, 
{"href":"\/pointsOfSale\/UUID.a12e7adf-652a-4197-91bf-d4785e43f09f", 
"model":{"href":"\/models\/modelePointOfSale", 
"modelType":{"href":"\/modelTypes\/pointOfSale"}}, 
"source":{"href":"\/sources\/Wikeo"}, 
"attribute":[ 
{"code":"pointOfSalePhysical","value":false}, 
{"code":"mail","value":"Mail1"}, 
{"code":"adresseMateriau","value":"Material address1"}]} 
}}

在整理后，我希望能够做这样的事情":

I would like to be able to do "something" like this after unmarshaling:

myJsonMapped.get("pointsOfSale").get("pointOfSale").get(0).get("source").get("href").equals("\/sources\/TEST") == true 

例如，使用Gson，我们可以执行这种解码:

For instance, with Gson we can do this kind of decoding:

new Gson().fromJson(json, Map.class); 

我知道我可以使用简单的bean或处理器等来完成此操作...

I know I can do this with a simple bean or processor etc...

我只想知道我可以使用本机JSON骆驼组件配置

I just want to know of I can do this more efficiently with a native JSON camel component config

我已经尝试了类似的其他操作: unmarshal().json()... 或者 unmarshal().json(JsonLibrary.Gson，Map.class).. 等等... 没有成功:'(

I tried different thing already like : unmarshal().json()... or unmarshal().json(JsonLibrary.Gson, Map.class).. etc... without succes :'(

推荐答案

您可以使用杰克逊做类似的事情.

You could do something like this with jackson.

<dataFormats>
  <json id="jack" library="Jackson"/>
</dataFormats>

...

<route>
  <from uri="direct:test"/>
  <unmarshal ref="jack"/>
  <process ref="something"/>
</route>

或在带有gson的Java中:

Or in java with gson:

 from("foo:bar")
    .unmarshal().json(JsonLibrary.Gson,Map.class)
    .to("foo:baz");

如果您无法使它正常工作，请指出错误，并排在第四位.

If you're not getting it to work, please state error and so fourth.

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