Perl中的JSON解析错误 [英] JSON parsing error in perl

问题描述

我收到错误

执行失败...格式不正确的JSON字符串，数组，对象，数字，字符串或原子都不是，字符偏移量为0(在((字符串的结尾)"之前))"

EXECUTION FAILED ...malformed JSON string, neither array, object, number, string or atom, at character offset 0 (before "(end of string)")"

当我将我的JSON字符串从数据库解析到此代码段时.

when I parse my JSON string from DB to this snippet.

my $json_geno1 = decode_json($geno_set_one);
warn Dumper($json_geno1); 

我想念什么吗? json字符串来自数据库.

Am I missing something ? The json string is from the Database.

 $VAR1 = [
   '{"":"No Call","rs1032807":"AG","rs718757":"AG","rs6557634":"CC","rs995553":"CG","rs6166":"AG","rs4925":"AA","rs502843":"GT","rs725029":"No Call","rs3904872":"GG","rs1402695":"TT","rs719601":"AA","rs2374061":"AG","rs952503":"TT","rs1801262":"AG","rs5215":"CT","rs978422":"CC","rs12828016":"GG","rs958388":"AG","rs999072":"CT","rs967344":"AG","rs2207782":"CC","rs349235":"AA","rs1074553":"CT","rs1395936":"AG","GS35220":"CT","rs7627615":"AG","rs727336":"AG","rs2077774":"AC","rs8065080":"CC","rs1131498":"TT","rs2247870":"No Call","rs803172":"TT","rs1541290":"AG","rs1414904":"AA","rs1928045":"No Call","rs2077743":"GT","rs2361128":"No Call","rs3795677":"AG","rs1030687":"CT","rs156318":"GG","rs952768":"CC","rs1363333":"TT","rs7298565":"AG","rs310929":"CC","rs2369898":"CT","rs1327118":"CC","rs4619":"AG","rs965323":"TT","rs2887851":"AG","rs1862456":"GT","rs6759892":"GT","rs753381":"AG","rs1805034":"CC","rs1812642":"AA","rs4075254":"CT","rs1805087":"AA","rs532841":"CT","rs951629":"GG","rs2286963":"GG","rs763553":"CT","rs1074042":"GG","rs2241714":"GG","rs894240":"TT","rs522073":"CT","GS35205":"TC","rs1368136":"TT","rs1426003":"GG","rs2016588":"No Call","rs621277":"No Call","rs727081":"GG","rs1392265":"AC","rs1079820":"No Call","rs4843075":"AG","rs156697":"CC","rs11096957":"AC","rs1952161":"GG","rs1961416":"AG","rs1585676":"GG","rs890910":"TT","rs171953":"AG","rs1843026":"CC","rs1515002":"CC","rs756497":"No Call","rs1293153":"No Call","rs754257":"GT","rs649058":"AG","rs726957":"AG","rs728189":"No Call","GS34251":"TC","rs3742207":"No Call","rs210310":"CT","rs2216629":"AG","rs1541836":"CT","rs722952":"CT","rs1105176":"GG"}'
    ];

谢谢

推荐答案

您可能应该使用:

my $json_geno1 = decode_json($VAR1[0]);

因为$VAR1现在是一个数组.

此JSON有效(我已经在PHP中对其进行了测试)，并且从该字符串中获取对象没有问题.

This JSON is valid (I've tested it in PHP) and I get object from this string without a problem.

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