PHP Web服务，用于在Android上验证用户登录 [英] PHP web service for authenticating user login on Android

问题描述

尝试在Android上进行用户身份验证工作.

Trying to get the user authentication work on Android.

Android应用程序使用POST方法发送用户名和密码.但是，我不断收到错误接收详细信息！"错误.我尝试使用REST控制台查看Web服务是否正常运行，但是没有成功，即使在那儿我也遇到相同的错误.

The Android app sends username and password using POST method. But, I keep getting "Error receiving detail!!" error. I tried to use REST console to see if the web service works, but no success, I get the same error even there.

任何帮助或指导将不胜感激.

Any help or direction would be appreciated.

已构建了一个PHP Web服务，代码为:

Have built a PHP web service and the code is:

<?php

require_once '../site_info.php';
require_once '../database_connect.php';
require_once '../functions.php';

if(isset($_REQUEST['email']) and $_REQUEST['email']!='' and isset($_REQUEST['password']) and $_REQUEST['password']!='')
{
    $email = mysql_real_escape_string($_REQUEST['email']);
    $pass = mysql_real_escape_string($_REQUEST['password']);

    $query = 'select id from users where email = "'.$email.'" and password = "'.sha1($pass).'"';
    $result=mysql_query($query) or die('error getting admin details : '.mysql_error());

    if(mysql_num_rows($result)==1)
    {
        echo 'Login Success!!';
    }
    else
    {
        echo 'Incorrect login details!!';
    }
}
else
{
    echo 'Error recieving data!!';
}

?>

Android应用将请求发送为json:

The Android app sends request as json:

JOSN请求数据:{密码":密码"，电子邮件":"[e-mail]"}

JOSN request data:{"password":"password","email":"[e-mail]"}

响应

状态:200

响应正文:数组(0){}接收数据出错！

response body:array(0) {}Error recieving data!!

推荐答案

找到了解决方法

<?php

require_once '../site.php';
require_once '../database.php';
require_once '../functions.php';

$data = file_get_contents('php://input');
$json = json_decode($data);

$email = $json->{'email'};
$password = $json->{'password'};

if(!empty($email) and !empty($password))
{
    $email = mysql_real_escape_string($email);
    $password = mysql_real_escape_string($password);

    $query = 'select id from users where email = "'.$email.'" and password = "'.sha1($password).'"';
    $result=mysql_query($query) or die('error getting admin details : '.mysql_error());

    if(mysql_num_rows($result)==1)
    {
        $array = array("success" => "TRUE");
        print(json_encode($array));
    }
    else
    {
        $array = array("error" => "Login invalid.");
        print( json_encode($array));
    }
}
else
{
    $array = array("error" => "Data not recieved.");
    print( json_encode($array));
}

?>

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