将json_encode应用到类时如何忽略特定值 [英] How to ignore specific values when applying json_encode to class
问题描述
在编码为json时,是否可以忽略php中某个类的特定类属性.
Is there a way to ignore specific class attributes of a class in php when encoding to json.
例如,在具有杰克逊库的Java中,我可以使用@JsonIgnore注释全局变量以实现此目的. php中有什么可比的(最好是本地的)吗?
For example in java with the jackson library I can annotate globals with @JsonIgnore to achieve this. Is there anything comparable (preferably native) in php??
推荐答案
一种方法是利用 JsonSerializable
接口一个>.这样,您可以创建在类上调用json_encode()
时调用的函数.
One method is to utilize the JsonSerializable
interface. This lets you create a function that's called when json_encode()
is called on your class.
例如:
class MyClass implements JsonSerializable{
public $var1, $var2;
function __construct($a1, $a2){
$this->var1 = $a1;
$this->var2 = $a2;
}
// From JsonSerializable
public function jsonSerialize(){
return ['var1' => $this->var1];
}
}
因此,当调用json_encode()
时,将仅对var1
进行编码.
So, when json_encode()
is called, only var1
will be encoded.
$myObj = new MyClass(10, 20);
echo json_encode($myObj); // {"var1":10}
注意:这仅适用于PHP 5.4 +
Note: This only works on PHP 5.4+
这篇关于将json_encode应用到类时如何忽略特定值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!