如何将值从一个视图传递到iOS中的另一个视图? [英] How can I pass the value from a view to another view in iOS?

问题描述

    import UIKit

    class TableController: UITableViewController {

    var items = NSMutableArray()
    var TableData:Array< String > = Array < String >()
    var json:String = ""

    var quantity2: Int = 0
    var shortDate: String = ""

    @IBOutlet var myTableView: UITableView!
    var arrayOfMenu: [Nutrisi] = [Nutrisi]()

    override func viewDidLoad() {
        super.viewDidLoad()
        self.setUpMenu()
        self.myTableView.delegate = self
        self.myTableView.dataSource = self
    }

    override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return arrayOfMenu.count
    }

    override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {

        let cell: CustomCell = tableView.dequeueReusableCellWithIdentifier("cell") as! CustomCell
        let menu = arrayOfMenu[indexPath.row]
        cell.setCell(menu.type, rightlabeltext: menu.unit, imagename: menu.image)
        var data = Nutritiondata(type: menu.type, amount: String(cell.value).toInt()!)
        var json = JSONSerializer.toJson(data)
        self.json = json
        return cell
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
    }

    func do_table_refresh()
    {
        dispatch_async(dispatch_get_main_queue(), {
            self.tableView.reloadData()
            return
        })
    }

    func setUpMenu()
    {

        var json: JSON = JSON (data: NSData())
        let frame:CGRect = CGRect(x: 110, y: 300, width: view.frame.width, height: 700)
        self.tableView.frame = frame
        DataManager.getnutritionsDataFromFileWithSuccess{ (data) -> Void in
            json = JSON(data: data)
            let results = json["results"]
            for (index: String, subJson: JSON) in results {
            }
            for (var i = 0; i < json["nutritions"].count; i++) {
                if let type = json["nutritions"][i]["type"].string {
                    if let icon: AnyObject = json["nutritions"][i]["icon"].string {
                        self.items.addObject(icon)
                        if let unit = json["nutritions"][i]["unit"].string {

                            dispatch_async(dispatch_get_main_queue(), {self.tableView!.reloadData()})
var menu = Nutrisi(type: type, unit: unit, image: icon as! String)
                                    self.arrayOfMenu.append(menu)
                                    self.TableData.append(type + unit )
                                    self.do_table_refresh();               
                        }
                    }
                }
            }
        }
    }
}

我已经有了这段代码，并且可以在表控制器视图上很好地工作，但是我想制作一个新的视图控制器，它可以打印json(表控制器上的json可以很好地工作并打印出来)

I've this code, and works well on table controller view, but I want to make a new view controller that prints json (json on table controller works well, and printed out)

因此，我将一个新的视图控制器连接到另一个名为senddata的类，该命令用于在该类上打印json，我想在按下按钮时打印该json数据:

So, I made a new view controller connected to another class named senddata what command that I should use to print json on there, I want to print that json data when the button pressed:

import UIKit

class SendData: UIViewController{

    @IBAction func tes(sender: AnyObject) {
        println()
    }

    override func viewDidLoad() {
        super.viewDidLoad()
    }    
}

推荐答案

您可以将JSON数据放在全局结构中，这样最终看起来像这样.

You could put that JSON Data in a global struct, so it would end up looking like this.

TableViewController.swift

TableViewController.swift

struct JSON {
  static var JSONData = ""
}

  class TableController: UITableViewController {

    var items = NSMutableArray()
    var TableData:Array< String > = Array < String >()
    var json:String = ""

    var quantity2: Int = 0
    var shortDate: String = ""

    @IBOutlet var myTableView: UITableView!
    var arrayOfMenu: [Nutrisi] = [Nutrisi]()

    override func viewDidLoad() {
        super.viewDidLoad()
        self.setUpMenu()
        self.myTableView.delegate = self
        self.myTableView.dataSource = self
    }

    override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return arrayOfMenu.count
    }

    override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {



        let cell: CustomCell = tableView.dequeueReusableCellWithIdentifier("cell") as! CustomCell
        let menu = arrayOfMenu[indexPath.row]
        cell.setCell(menu.type, rightlabeltext: menu.unit, imagename: menu.image)
        var data = Nutritiondata(type: menu.type, amount: String(cell.value).toInt()!)
        var json = JSONSerializer.toJson(data)
        JSON.JSONData = json
        return cell
    }

SendData.swift

SendData.swift

class SendData: UIViewController{

    @IBAction func tes(sender: AnyObject) {
        println(JSON.JSONData)
    }

    override func viewDidLoad() {
        super.viewDidLoad()

    }

}

这篇关于如何将值从一个视图传递到iOS中的另一个视图?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！