将Pandas Dataframe转换为嵌套的json [英] Convert a Pandas Dataframe into a nested json
问题描述
我需要将pandas Dataframe转换为嵌套的json. .to_json的输出给出以下内容
I need to convert pandas Dataframe into nested json. The output of .to_json gives the following
{"Annual Expenditure":{"0":250,"1":250},"Annual Frequency":{"0":1,"1":1},"Avg days":{"0":null,"1":null},"First visit":{"0":1449100800000,"1":1490054400000},"Frequency":{"0":1,"1":1},"Guest":{"0":25642,"1":55521},"Last visit":{"0":1449100800000,"1":1490054400000},"Monetory":{"0":250,"1":250},"Recency":{"0":701,"1":227},"Visit_Ids":{"0":[80611],"1":[342104]},"RFMClass":{"0":"444","1":"144"},"AvgLTV":{"0":13305.7692307692,"1":13305.7692307692}}
但是我需要在嵌套的json中将key作为guest_id并有相应的值.像这样:
But I need in a nested json with key as the guest_id and there corresponding values. Something like this:
{55521: {'Monetory': 250, 'First visit': datetime.date(2017, 3, 21), 'Annual Expenditure': 250, 'Frequency': 1, 'Last visit': datetime.date(2017, 3, 21), 'Avg days': NaT, 'Annual Frequency': 1, 'Recency': 227, 'Visit_Ids': [342104]}, 25642: {'Monetory': 250, 'First visit': datetime.date(2015, 12, 3), 'Annual Expenditure': 250, 'Frequency': 1, 'Last visit': datetime.date(2015, 12, 3), 'Avg days': NaT, 'Annual Frequency': 1, 'Recency': 701, 'Visit_Ids': [80611]}}
.to_json()函数无法按我想要的方式工作,我已经用尽了我所有的选择.任何想法如何进行?
The .to_json() function doesn't work the way I want it and I have pretty much exhausted all my options on this. Any Idea how to proceed ?
感谢您的回答!我将json输出作为循环的一部分,而我得到的每个输出都是一个唯一的JSON.那么有什么方法可以创建以下内容?:
Thanks for the answer! I'm getting json outputs as part of a loop, and each output I get is a unique JSON. So is there a way to create the following ?:
{45: {"50492":{"Annual Expenditure":1000,"Annual Frequency":1,"Avg days":null,"First visit":1486339200000,"Frequency":1,"Last visit":1486339200000,"Merchants":45,"Monetory":1000,"Recency":270,"Visit_Ids":[300758],"RFMClass":"144","AvgLTV":113800.0},"1041":{"Annual Expenditure":1000,"Annual Frequency":1,"Avg days":null,"First visit":1478649600000,"Frequency":1,"Last visit":1478649600000,"Merchants":45,"Monetory":1000,"Recency":359,"Visit_Ids":[257022],"RFMClass":"244","AvgLTV":113800.0},"783":{"Annual Expenditure":1000,"Annual Frequency":1,"Avg days":null,"First visit":1457049600000,"Frequency":1,"Last visit":1457049600000,"Merchants":45,"Monetory":1000,"Recency":609,"Visit_Ids":[123464],"RFMClass":"444","AvgLTV":113800.0}}}
这里的45是一个唯一的标识符,我将在循环结束时传递它.
Here the 45 is a unique identifier that I'll pass in at the end of the loop.
推荐答案
使用 set_index
+
{
"25642": {
"Annual Expenditure": 250,
"Annual Frequency": 1,
"Avg days": null,
"AvgLTV": 13305.7692307692,
"First visit": 1449100800000,
"Frequency": 1,
"Last visit": 1449100800000,
"Monetory": 250,
"RFMClass": "444",
"Recency": 701,
"Visit_Ids": [80611]
},
"55521": {
"Annual Expenditure": 250,
"Annual Frequency": 1,
"Avg days": null,
"AvgLTV": 13305.7692307692,
"First visit": 1490054400000,
"Frequency": 1,
"Last visit": 1490054400000,
"Monetory": 250,
"RFMClass": "144",
"Recency": 227,
"Visit_Ids": [342104]
}
}
输入DataFrame
:
d = {"Annual Expenditure":{"0":250,"1":250},"Annual Frequency":{"0":1,"1":1},"Avg days":{"0":np.nan,"1":np.nan},"First visit":{"0":1449100800000,"1":1490054400000},"Frequency":{"0":1,"1":1},"Guest":{"0":25642,"1":55521},"Last visit":{"0":1449100800000,"1":1490054400000},"Monetory":{"0":250,"1":250},"Recency":{"0":701,"1":227},"Visit_Ids":{"0":[80611],"1":[342104]},"RFMClass":{"0":"444","1":"144"},"AvgLTV":{"0":13305.7692307692,"1":13305.7692307692}}
df = pd.DataFrame(d)
print (df)
Annual Expenditure Annual Frequency Avg days AvgLTV \
0 250 1 NaN 13305.769231
1 250 1 NaN 13305.769231
First visit Frequency Guest Last visit Monetory RFMClass Recency \
0 1449100800000 1 25642 1449100800000 250 444 701
1 1490054400000 1 55521 1490054400000 250 144 227
Visit_Ids
0 [80611]
1 [342104]
j = df.set_index('Guest').to_json(orient='index')
j_final = {45: j}
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