如何从Zend Framework 3的响应中获取有效的JSON输出? [英] How get a valid JSON output from the response in Zend Framework 3?

问题描述

我正在为API编写客户端...

I'm writing a client for an API...

use Zend\Http\Client;
use Zend\Http\Request;
use Zend\Json\Json;
...
$request = new Request();
$request->getHeaders()->addHeaders([
    'Accept-Charset' => 'UTF-8',
    'Accept' => 'application/hal+json',
    'Content-Type' => 'application/hal+json; charset=UTF-8',
]);
$apiAddress = 'http://my.project.tld/categories';
$request->setUri($apiAddress);
$request->setMethod('GET');
$client = new Client();
$response = $client->dispatch($request);
$data = $response->getContent();

...并得到像这样的损坏的JSON:

... and get a broken JSON like this:

1f9e <-- What is it?
{"_links...
\u043 <-- What is it?
1a6...
tfoli <-- What is it?
0

该字符串分为五行:

• 第一行:仅1f9e
• 第二行:第一部分内容
• 3d行:字符串1a6
• 第四行:第二个内容部分
• 第五行:0

• 1st line: only 1f9e
• 2nd line: first content part
• 3d line: string 1a6
• 4th line: the second content part
• 5th line: 0

为什么我会得到其他符号/字符串?如何避免这种情况获得有效的JSON输出?

推荐答案

响应对象的getContent()方法存在问题.它可能不会解码从请求中获取的内容.请在此处中查看.这可能是原因.我可能是错的！

The problem with the getContent() method of the response object. It may not decode the content it gets in it from the request. Please have a look at here. This might be the reason. I may be wrong!

因此，它的getBody()方法对请求的内容进行解码工作.因此，请使用此方法代替getContent().

So the getBody() method of it does the decoding job for the content of the request. So please use this method instead of getContent().

$data = $response->getBody();

希望这对您有帮助！

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