如何在CURL POST命令中将JSON文件作为请求正文的一部分发送 [英] How to send JSON file as part of request body in CURL POST command

问题描述

我正在使用CURL命令行将HTTP POST发送到Web服务.我想将文件内容作为POST命令正文的 PART 包含在内.这可能吗?我知道我可以按照此处的方式发送整个文件.但是我只希望正文的一部分成为文件的内容.

I am using CURL command line to send HTTP POST to a web service. I want to include a file's contents as a PART of the body of the POST command. Is this possible? I know I can send a file as the entire body as answered here. But I only want a part of the body to be the content of the file.

例如

curl -d '{ "name": "rahul", "speed": "fast", "data": { "number": 1, "letter": "abd", "letter2": "efg"} }' 'http://...'

在这里，我只想将data作为文件的内容.不是整个身体.我该怎么办?

Here I only want data as the file's content. Not the entire body. How can I do this?

推荐答案

设置一个变量以包含文件内容:

Set a variable to contain the file contents:

data=$(cat filename)

然后将其替换为JSON:

then substitute it into the JSON:

curl -d '{ "name": "rahul", "speed": "fast", "data": ' "$data" ' }' 'http://...'

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