jQuery加载JSON [英] jQuery Load JSON
问题描述
我有一个小难题,希望应该很容易解决.
I've got a small dilemma, that should hopefully be easy to resolve.
我正在使用jQuery/JSON/PHP加载一些数据-本质上,正在加载的数据是几个<li>
元素.
I am loading some data using jQuery/JSON/PHP-- essentially, the data being loaded are several <li>
elements.
以下代码可以正常工作:
The following code works correctly:
function load_list() {
$.getJSON('json/load.php', function(data) {
$.each(data, function(k, v){
$("#my_div").append('
<li> \
<div> \
<input type="checkbox"> \
</div> \
<div>'+v.due_date+'</div> \
<h3> \
<span>'+v.title+'</span> \
</h3> \
</li> \
');
});
});
}
但是,假设我要更新"#my_div"
并稍后(例如,每20秒一次)再次调用该函数.如果我重新调用上面的函数,它实际上会再次追加项目,从而复制结果.
However, let's say I want to update "#my_div"
and call the function again later on, say, every 20 seconds. If I re-call the function above, it actually appends the items again, thus duplicating the results.
我的问题是(原谅我不知道):如何重写上面的函数以加载所有事件并刷新它,并将"#my_div"
的HTML设置为全新的而不是不重复?
My question is (forgive me for not knowing): How can I rewrite the function above to load all events and refresh it and set the HTML of the "#my_div"
to be brand new and not to not duplicate?
非常感谢.
推荐答案
在包含.each()
调用的匿名函数的开始处调用$("#my_div").empty()
.
Call $("#my_div").empty()
at the beginning of the anonymous function containing the .each()
call.
这篇关于jQuery加载JSON的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!