如何从月份为当前月的列中的SQL日期中选择月份 [英] How to select month from sql date in column where month is currentmonth

问题描述

我需要做出一条选择语句，从客户WHERE返回Voornaam，Tussenvoegsel，Achternaam(我的数据库中有一列名为Geboortedatum，在这里我有一个日期.我需要上面命名的值，其中Geboortedatum是与$currentmonth相同.我已经有一个返回currentmonth的json函数.) 需要明确说明的是:我需要Voornaam，Tussenvoegsel和Achternaam，其中来自表客户的Geboortedatum(DD-MM-YYYY)月与$currentmonth相同.

I need to make a select statement that returns Voornaam, Tussenvoegsel, Achternaam from customer WHERE (I have a column in my database which is called Geboortedatum, in here I have a date. I need al the values named above where Geboortedatum is the same as $currentmonth. I already have a json function which returns the currentmonth.) I am stuck with what to put after WHERE. Just to be clear: I need Voornaam, Tussenvoegsel and Achternaam where the month of Geboortedatum(DD-MM-YYYY) from my table customer is the same as $currentmonth.

$conn = new mysqli("localhost", "root", "Habt2002", "fca");

if ($_POST['key'] == 'bijnaJarig') {
    $currentmonth = $conn->real_escape_string($_POST['currentmonth']);
    $sql = $conn->query("SELECT Voornaam, Tussenvoegsel, Achternaam, Telefoonnummer, Email 
                        FROM customer 
                        WHERE ??????? ");
    $data = $sql->fetch_array();
    $jsonArray = array(
        'voornaam' => $data['Voornaam'],
        'tussenvoegsel' => $data['Tussenvoegsel'],
        'achternaam' => $data['Achternaam'],
        'telefoonnummer' => $data['Telefoonnummer'],
        'emailbijnajarig' => $data['Email']
    );

    exit(json_encode($jsonArray));
}

推荐答案

使用MONTH()和CURDATE() MySQL函数，您可以执行

Using the MONTH() and CURDATE() MySQL functions you can do

WHERE MONTH(Geboortedatum) = MONTH(CURDATE())

您可能还想添加YEAR()支票

AND YEAR(Geboortedatum) = YEAR(CURDATE())

除非您希望获得本月中所有年份的所有数据

unless you want all data for this month over multiple years

您仅从结果集中获取一行，您要么需要遍历结果集中的n行，要么使用fetch_all()方法.在这种情况下，fetch_all()似乎是最简单的方法.

You are only fetching ONE row from the resultset, you either need to loop over the n rows in the resultset OR use the fetch_all() method. In this case the fetch_all() seems like the simplest approach.

$conn = new mysqli("localhost", "root", "xxxx", "fca");
if (!$conn) {
    echo "Error: Unable to connect to MySQL." . PHP_EOL;
    echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
    echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
    exit;
}

if ($_POST['key'] == 'bijnaJarig') {

    $sql = $conn->query("SELECT Voornaam, Tussenvoegsel, Achternaam, Telefoonnummer, Email 
                        FROM customer 
                        WHERE MONTH(Geboortedatum) = MONTH(CURDATE())");
    $all_rows= $sql->fetch_all();

    echo json_encode($all_rows);
}

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