Java Objective-C Json数据 [英] Java Objective-C Json data

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本文介绍了Java Objective-C Json数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我也不太了解Objective-C中的代码行:

I have a little problem with understanding this too lines of code in Objective-C :

id jsonData;
NSInteger errorCode;
NSString* errorString;
errorCode = [jsonData sqlInt:@"error_code"];
errorString = [[jsonData objectForKey:@"error_string"] retain];

我试图找到一种方法来用Java执行相同的代码,这就是为什么我需要一点帮助来理解这段代码的原因. 预先谢谢!!!

I'm trying to find a way how to do the same code in Java,that's why I need a little help to understand this piece of code. Thanks in advance!!!

该代码与目标C中的代码相同吗? :

Is this code do the same as in Objective C? :

 ErrorCode = new JSONObject();
    ErrorCode.put("error_code", errorCode);
    ErrorString = new JSONObject();
    ErrorString.put("error_string", errorString);

推荐答案

尝试一下,

SBJSON *jsonData = [SBJSON alloc]init]; - Objective c

private JSONObject jObject; - Java

//您将获得一个JSON数据-目标C

// you get a JSON Data - Objective C

NSDictionary *errorString = [[jsonData objectForKey:@"error_string"] retain];

对于Java-

jObject = new JSONObject(errorString); 

JSONArray menuitemArray = popupObject.getJSONArray("error_string");

String attributeValue = jObject.getString("value");

System.out.println(attributeValue);

这篇关于Java Objective-C Json数据的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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