将列表中的项目更改为json中的键 [英] Change item in a list to a key in json

问题描述

我有类似的字段列表-

required_fields = ["server['server_name']","server['server_info']['asset_type']['display_name']",
                   "server['asset_status']['display_name']", "server['record_owner']['group_name']",
                   "server['server_total_cost_of_ownership']['description']",
                   "server['primary_business_owner']['name']", "server['environment']['display_name']",
                   "server['is_virtual']", "server['managed_by']['display_name']",
                   "server['server_info']['billable_ibm']", "server['server_info']['billing_sub_type']['display_name']",
                   "server['server_info']['serial_number']", "", "server['location']['display_name']",
                   "server['inception_date']", "server['server_info']['decommission_date']" ]

每个代表一个JSON文件中的键，我想获取其中的值以转换为CSV.如果我执行以下操作:

Each one represents a key in a JSON file I want to get the values out of to transform into CSV. If I do the following:

for server in server_list:
    for item in required_fields:
        print item

所有要做的就是从键中的每个项目返回字符串值.我要它做的就是为我提供与键关联的值.

all is does is return the string value from each item in the key. What I want it to do is give me the value that is associated with the key.

因此，例如上面的代码print item给我server['server_name']而不是torservapp001

So as an example in the above code print item is giving me server['server_name'] and not torservapp001

推荐答案

您正在寻找的是 eval :

What you are looking for is eval:

for server in server_list:
  for item in required_fields:
    print(eval(item))

eval将运行"一个字符串，就好像它是纯代码一样.例如，

eval will "run" a string as if it were plain code. For example,

eval('print("foo")')
print("foo")

两者给出相同的结果.

必填项:如果要执行的代码源可能不受信任，请不要使用eval.在这种情况下，或者如果您不确定，请查看其他答案.

Mandatory Note: Please don't use eval if the source of the code to execute is potentially untrusted. See the other answer in this case, or if you are unsure.

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