如何在JSON数据Laravel 5.1中查询生成器 [英] How to Query Builder in json data laravel 5.1
本文介绍了如何在JSON数据Laravel 5.1中查询生成器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何在json数据中查询生成器?我正在使用guzzle,所有我想要如何查询,例如搜索金额不为NULL的数据?
how to query builder in json data? i'm using guzzle , all i want how to query like searching data where amount is NOT NULL?
json数据结果:
{
"amount": [
{
"member_id": "SSD",
"sum4": null,
"sum5": null,
"sum6": null
},
{
"member_id": "OGG",
"sum4": 122,
"sum5": 242,
"sum6": 123
},
{
"member_id": "PUCAN",
"sum4": 123,
"sum5": 443,
"sum6": 222
},
{
"member_id": "SS3TG",
"sum4": null,
"sum5": null,
"sum6": null
}
]
}
我只想在JSON结果中不获取sum4,sum6,sum6的地方,你们能帮助我吗?.
ALL I WANT HOW TO GET sum4,sum6,sum6 WHERE NOT NULL IN JSON RESULT, can u guys help me..
推荐答案
// Pass JSON data with true as parameters to json_decode function
// It returns value as associative array
$data = json_decode($jsonData, true);
// Loop through amount
foreach($data['amount'] as $sum)
{
// Check sum is not null
if ($sum['sum4'] != null) {
echo $sum['sum4'];
// Check sum is not null
} elseif ($sum['sum5'] != null) {
echo $sum['sum5'];
// Check sum is not null
} elseif ($sum['sum6'] != null) {
echo $sum['sum6'];
}
}
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