Swift 3-提取JSON数据 [英] Swift 3 - Extract JSON data
本文介绍了Swift 3-提取JSON数据的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我有以下JSON
{
"results" : [
{
"address_components" : [
{
"long_name" : "OL12 7LD",
"short_name" : "OL12 7LD",
"types" : [ "postal_code" ]
},
{
"long_name" : "Ings Lane",
"short_name" : "Ings Ln",
"types" : [ "route" ]
},
{
"long_name" : "Rochdale",
"short_name" : "Rochdale",
"types" : [ "postal_town" ]
},
{
"long_name" : "Greater Manchester",
"short_name" : "Greater Manchester",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "England",
"short_name" : "England",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "United Kingdom",
"short_name" : "GB",
"types" : [ "country", "political" ]
}
],
"formatted_address" : "Ings Ln, Rochdale OL12 7LD, UK",
"geometry" : {
"bounds" : {
"northeast" : {
"lat" : 53.6307898,
"lng" : -2.1838913
},
"southwest" : {
"lat" : 53.62996279999999,
"lng" : -2.1857861
}
},
"location" : {
"lat" : 53.63032279999999,
"lng" : -2.1847775
},
"location_type" : "APPROXIMATE",
"viewport" : {
"northeast" : {
"lat" : 53.6317252802915,
"lng" : -2.183489719708498
},
"southwest" : {
"lat" : 53.6290273197085,
"lng" : -2.186187680291502
}
}
},
"place_id" : "ChIJSzEfAAi8e0gREDjvGtRJwLM",
"types" : [ "postal_code" ]
},
{
"address_components" : [
{
"long_name" : "OL12",
"short_name" : "OL12",
"types" : [ "postal_code", "postal_code_prefix" ]
},
{
"long_name" : "Rochdale",
"short_name" : "Rochdale",
"types" : [ "postal_town" ]
},
{
"long_name" : "England",
"short_name" : "England",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "United Kingdom",
"short_name" : "GB",
"types" : [ "country", "political" ]
}
],
"formatted_address" : "Rochdale OL12, UK",
"geometry" : {
"bounds" : {
"northeast" : {
"lat" : 53.6895598,
"lng" : -2.1106483
},
"southwest" : {
"lat" : 53.6127321,
"lng" : -2.2874164
}
},
"location" : {
"lat" : 53.66276999999999,
"lng" : -2.187286
},
"location_type" : "APPROXIMATE",
"viewport" : {
"northeast" : {
"lat" : 53.6895598,
"lng" : -2.1106483
},
"southwest" : {
"lat" : 53.6127321,
"lng" : -2.2874164
}
}
},
"place_id" : "ChIJt3p6tTS5e0gRCt658WmnJVM",
"types" : [ "postal_code", "postal_code_prefix" ]
},
{
"address_components" : [
{
"long_name" : "Northwest Edmond Airport",
"short_name" : "Northwest Edmond Airport",
"types" : [ "establishment", "point_of_interest" ]
},
{
"long_name" : "Edmond",
"short_name" : "Edmond",
"types" : [ "locality", "political" ]
},
{
"long_name" : "Oklahoma County",
"short_name" : "Oklahoma County",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "Oklahoma",
"short_name" : "OK",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "United States",
"short_name" : "US",
"types" : [ "country", "political" ]
},
{
"long_name" : "73025",
"short_name" : "73025",
"types" : [ "postal_code" ]
}
],
"formatted_address" : "Northwest Edmond Airport, Edmond, OK 73025, USA",
"geometry" : {
"location" : {
"lat" : 35.7075513,
"lng" : -97.54059719999999
},
"location_type" : "APPROXIMATE",
"viewport" : {
"northeast" : {
"lat" : 35.70890028029149,
"lng" : -97.53924821970848
},
"southwest" : {
"lat" : 35.7062023197085,
"lng" : -97.5419461802915
}
}
},
"place_id" : "ChIJvTkNtm72sYcRZRzH8Qx2q_o",
"types" : [ "airport", "establishment", "point_of_interest" ]
}
],
"status" : "OK"
}
以及以下要调用的代码，并尝试从中提取所需的数据:
And the following code to call and try to extract the data I need from it:
Alamofire.request(requestURL).responseString { response in
debugPrint(response)
if let json = response.result.value {
if let data = json.data(using: String.Encoding.utf8) {
let json = JSON(data: data)
for result in json["location"].arrayValue {
print(result["lat"].stringValue)
print(result["lng"].stringValue)
}
}
}
}
}
我的问题是我不确定如何提取想要的部分，即第一场比赛的位置部分下的"lat"和"lng".我正在使用Alamofire和SwiftyJSON
My problem is I'm not sure how to extract the part I want, which is 'lat' and 'lng' under the location section of the first match. I am using Alamofire and SwiftyJSON
JSON正确返回，因此没有问题.
The JSON is coming back correctly so there is no issue there.
推荐答案
根对象是一个包含键status和results的字典.您必须检查status是否为"OK"，并获取键results的数组:
The root object is a dictionary containing the keys status and results. You have to check if the status is "OK" and get the array for key results:
if let status = json["status"].string, status == "OK", let results = json["results"].array {
for result in results {
if let location = result["geometry"]["location"].dictionary {
let longitude = location["lng"]!.doubleValue
let latitude = location["lat"]!.doubleValue
print(longitude, latitude)
}
}
}
仔细阅读JSON，有关结构的清单非常清楚.
Read the JSON carefully, the listing is very clear regarding the structure.
-
[]表示一个数组. -
{}代表字典. - 双引号中的值为
String. - 不带双引号的值是
Int，Double(包括点)或Bool(true或false). -
null被桥接到NSNull.
[]represents an array.{}represents a dictionary.- values in double quotes are
String. - values without double quotes are
Int,Double(including dot) orBool(trueorfalse). nullis bridged toNSNull.
这篇关于Swift 3-提取JSON数据的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
查看全文
