正确使用Newtonsoft Json ItemConverterType的方法 [英] Proper way of using Newtonsoft Json ItemConverterType

问题描述

我有一些错误的数据是从Web服务返回的，我无法更改.该服务返回一个JSON客户列表.在此列表中，每个客户还具有一个作业列表.但是返回的JSON是作业的字符串.

I have some bad data coming back from a web service which I cannot change. The service returns a JSON list of customers. Inside this list, each customer also has a list of jobs. But the JSON coming back is a string for the jobs.

因此:工作:"[]" ，而不是工作:[]

所以我将类定义为

[JsonProperty(PropertyName = "JOBS", ItemConverterType = typeof(StringToJobsConverter))]
public List<JobClass> Jobs { get; set; }

我创建了该类，并在其中创建了转换方法，如下所示:

I created the class, and created the conversion method inside it as follows:

return JsonConvert.DeserializeObject<List<JobClass>>(existingValue.ToString());

没有运气.重新调整的错误是无法将System.String强制转换或转换为System.Collections.Generic.List`1 [AppNamespace.JobClass] .

No luck. The error retuned is Could not cast or convert from System.String to System.Collections.Generic.List`1[AppNamespace.JobClass].

转换器代码中的断点永远不会被击中.有人可以看到我在做什么错吗?

Breakpoints in the converter code are never hit. Can anyone see what I'm doing wrong?

更新

我找到了问题，但不知道如何解决.该转换器将应用于列表内的JobClass.不去列表本身.我希望转换器仅将一次应用于列表反序列化.而是将其应用于列表中的每个JobClass记录.

I found the issue but don't know how to fix. The converter is being applied to the JobClass inside the list. Not to the List itself. I want the converter applied one time only to the List deserialization. Instead it's applied to each JobClass record inside the list.

推荐答案

string json = @"{str1:""abc"",list:""[1,2,3]"", str2:""def""}";
var temp = JsonConvert.DeserializeObject<Temp>(json);

public class Temp
{
    public string str1;
    [JsonConverter(typeof(StringConverter<List<int>>))]
    public List<int> list;
    public string str2;
}

public class StringConverter<T> : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        throw new NotImplementedException();
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        return JsonConvert.DeserializeObject<T>((string)reader.Value);
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}

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