单击JSP页面中的链接后，如何将请求转发到另一个JSP页面? [英] How to forward the request to another JSP page upon click of a link in a JSP page?

问题描述

我在jsp页面中有一个链接，单击链接后，如何将请求转发到另一个jsp页面.

I have a link in the jsp page, upon the link click, how can I forward the request to another jsp page.

推荐答案

如果您只想获取一个新的jsp，则只需

If you just want to GET a new jsp then simply

<a href="/jsp/newJsp.jsp">Click Here</a>

注意:到jsp的路径将从/公用Web空间开始，该公共目录与WEB-INF所在的目录相同

Note: the path to jsp will start from / the public web space the same dir where WEB-INF resides

如果您是指 forward ，则

if you mean forward then

点击后，您将执行GET操作，所以可以说

Upon click you will perform GET operation , So lets say

您单击

<a href="/yourApp/ForwardServlet/">Click Here</a>

在web.xml中创建一个Servlet条目，并将其映射到/ForwardServlet到ForwardServlet并在Servlet中执行

make a Servlet entry in web.xml and map it to /ForwardServlet to ForwardServlet and in Servlet perform

public class ForwardServlet extends HttpServlet{

    protected void doGet(HttpServletRequest request, HttpServletResponse response)             throws ServletException, IOException {


        String destination = "/WEB-INF/pages/result.jsp";

        RequestDispatcher rd = getServletContext().getRequestDispatcher(destination);
        rd.forward(request, response);
    }

}

引用:

• Servlet

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