如何获取此变量的值? [英] How can I get the value of this variable?

问题描述

在注销功能中，我需要获取$ time的值.用户登录时，该变量是在其他函数中声明的.

In logout function, I need to get the value of $time. This variable was declared in other function, when user logged in.

Broadcast::channel('chat', function ($user) {
        $ip = Request::ip();
        $time = now();  
        if (auth()->check() && !session()->has('name'))  {  
            UserInfo::storeUser();
            session()->put('name',$user->name);
            return [
                'id' => $user->id,
                'ip' => $ip,
                'name' => $user->name,
                'joined' => $time,                   
            ];
        }
    });

当用户注销时，我必须检查他的"id"和"joined"的值.我该怎么办?

When user logged out, I have to check his 'id' and value of 'joined'. How can I do this?

public function logout() {
       $id = auth()->id();
       $info = \App\UserInfo::where('id', $id)
                             -> where('joined', $time)
                             ->update(['left' => now()]);
        auth()->logout();
        session()->forget('name');
        session()->put('left',now());
        return redirect('/');
    }

推荐答案

您必须使用主唯一键作为ID，并创建一列"user_id"以在其中存储auth()-> id桌子.在加入/启动登录会话时，将"id"存储在应用程序中作为"session_id".

You must use a primary unique key as id and make a column 'user_id' for storing the auth()->id in the table. While joining/starting log in session, store the 'id' in application as 'session_id'.

您可以通过使用id来获得"joined"值，

You can get the 'joined' value by using id as follows,

$joined = \App\UserInfo::where('id', auth()->session_id)
          ->select('joined')
          ->first()
          ->joined;

在会话结束时，使用以下ID更新左侧的详细信息，

At end of session, update the left details with the id as follows,

 $info = \App\UserInfo::where('id', auth()->session_id)
            ->update(['left' => now()]);

这篇关于如何获取此变量的值?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！