如何在laravel 5.2中传递联接数组以选择查询 [英] how to pass array of joins to select query in laravel 5.2
问题描述
我正在尝试从多个表中获取数据.我已将join语句存储在$ Joins数组中,并将该数组传递给model
这是我到目前为止尝试过的-
I am trying to fetch data from multiple tables. I have stored join statements in a $Joins array and passed that array to model
Here is what I tried so far -
$tbl_name="user_master";
$select= ['user_master.*', 'country.country_name', 'city.city_name', 'login_master.email_id', 'login_master.password'];
$joins=[
"'country', 'user_master.country_id', '=', 'country.country_id'",
"'city', 'user_master.city_id', '=', 'city.city_id'",
"'login_master', 'user_master.user_id', '=', 'login_master.user_id'"
];
$users=$obj->getdata($tbl_name,$select,$joins);
模型-
public function getdata($tbl_name,$select,$joins)
{
$users = DB::table($tbl_name)
->join($joins)
->select($select)
->paginate(5);
return $users;
}
我正在尝试传递$ joins数组进行查询,但显示错误-
缺少Illuminate \ Database \ Query \ Builder :: join()的参数2,该参数在第61行的/opt/lampp/htdocs/demo_laravel/app/Models/Userdata.php中调用并已定义
I am trying to pass $joins array to query but it showing error -
Missing argument 2 for Illuminate\Database\Query\Builder::join(), called in /opt/lampp/htdocs/demo_laravel/app/Models/Userdata.php on line 61 and defined
如果我尝试--
$users = DB::table($tbl_name)
->join('country', 'user_master.country_id', '=', 'country.country_id')
->join('city', 'user_master.city_id', '=', 'city.city_id')
->join('login_master', 'user_master.user_id', '=', 'login_master.user_id')
->select($select)
->paginate(5);
return $users;
它工作正常,但是当我将数组传递给联接时显示错误.
如何解决?
请帮助我.
It is working fine but when I pass array to joins it shows error.
How to solve it?
Please help me.
推荐答案
尝试一下:
$joins
的格式:
$joins = [
['country', 'user_master.country_id', '=', 'country.country_id'],
['city', 'user_master.city_id', '=', 'city.city_id'],
['login_master', 'user_master.user_id', '=', 'login_master.user_id'],
];
和型号:
public function getdata($tbl_name, $select, $joins)
{
$users = DB::table($tbl_name);
foreach ($joins as $join) {
$users = $users->join(...$join);
}
$users = $users
->select($select)
->paginate(5);
return $users;
}
这篇关于如何在laravel 5.2中传递联接数组以选择查询的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!