如何在laravel中将新数据插入存在行而不替换现有数据? [英] How to insert new data into exists row without replace exists data in laravel?
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问题描述
这里我使用updateOrCreate
方法发布数据,但是当我使用此方法时,旧数据替换为新数据,但是我想添加新数据而不更新或替换现有数据.
Here I used updateOrCreate
method to post data but when I use this method old data replaced by new data but I want to add new data without updating or replacing exists data.
这是插入数据的代码
$booking = Bookings::updateOrCreate(
['schedules_id' => $schedules_id], // match the row based on this array
[ // update this columns
'buses_id' => $buses_id,
'routes_id' => $routes_id,
'seat' => json_encode($seat),
'price' => $request->price,
'profile' => 'pending',
]
);
推荐答案
我解决了自己,我将旧数据存储到$ extSeat中,然后与新数据合并,我不知道逻辑是对还是错,但是可以正常工作
I solved myself, I stored old data into $extSeat then merge with new data, I don't know the logic is correct or wrong but works
$extSeat = DB::table('bookings')->select('seat')->first();
$extSeat = explode(",", $extSeat->seat);
$booking = Bookings::updateOrCreate(
['schedules_id' => $schedules_id],// row to test if schedule id matches existing schedule id
[ // update this columns
'buses_id' => $buses_id,
'routes_id' => $routes_id,
'seat' => implode(",", array_merge($seat,$extSeat )),
'price' => $request->price,
'profile' => 'pending',
]);
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