查找文件并仅打印其父目录 [英] Find files and print only their parent directories

问题描述

我有以下命令.无论在哪里存在.user.log文件，我们都需要打印父目录(即hht和wee1.)如何做到这一点?

I have the following commands. Wherever the .user.log file is present, we need to print the parent directories (i.e hht and wee1.) How can this be done?

$ cd /nfs//office/ && find . -name '.user.log'
./hht/info/.user.log
./wee1/info/.user.log

推荐答案

我在这里缺少什么吗?当然，不需要所有这些正则表达式和/或循环，单线即可完成工作.当路径名中有空格时，"$()中的for foo"解决方案也将失败.

Am I missing something here. Surely all this regex and/or looping is not necessary, a one-liner will do the job. Also "for foo in $()" solutions will fail when there are spaces in the path names.

只需使用xargs两次使用dirname，即可获取父级的父级...

Just use dirname twice with xargs, to get parent's parent...

# make test case
mkdir -p /nfs/office/hht/info
mkdir -p /nfs/office/wee1/info
touch /nfs/office/hht/info/.user.log
touch /nfs/office/wee1/info/.user.log

# parent's parent approach
cd /nfs//office/ && find . -name '.user.log' | xargs -I{} dirname {} | xargs -I{} dirname {}

# alternative, have find print parent directory, so dirname only needed once...
cd /nfs//office/ && find . -name ".user.log" -printf "%h\n"  | xargs -I{} dirname {}

生产

./hht
./wee1

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