运行C程序的Linux脚本 [英] linux script running c program

问题描述

我试图在linux中运行脚本来运行c程序 脚本如下

i tried to run a script in linux to run a c program the script was as follows

#!/bin/bash
`gcc odd.c -o odd222`
`chmod +x odd222`
echo `./odd222`

而奇数c是

main()
{
int i;
printf("enter the no.");
scanf("%d",&i);
printf("shiv");
}

但是问题是，当我运行此脚本时，所有scanf语句都将被执行，然后所有输出都会显示出来…….

but the problem is that when i run this script the all the scanf statement are executed then all the outputs are shown simentaniously....

如果我没有在./odd222之前放置echo，则表示输入错误，找不到命令(输入" printf中的第一个元素.

if i do not put echo before ./odd222 then it says error enter command not found("enter" the first element in printf.

请帮助我

推荐答案

摆脱掉反引号，chmod和echo.您所需要做的就是运行gcc，然后运行您的程序.

Get rid of the backticks, the chmod, and the echo. All you need to do is run gcc, then run your program.

#!/bin/bash
gcc odd.c -o odd222
./odd222

如果编译成功，仅尝试运行该程序也很好.您可以使用&&将其设置为有条件.

It'd also be good to only try to run the program if it compiles successfully. You can make it conditional by using &&.

#!/bin/bash
gcc odd.c -o odd222 && ./odd222

修改C代码以确保立即打印输出也将是一件好事.输出通常是行缓冲的，这意味着只有在您写完最后一行换行符\n的全行时才显示.您将要打印换行符:

It'd also be good to modify your C code to ensure the printouts are printed immediately. Output is usually line buffered, meaning it's only displayed once you write a full line with a newline \n at the end. You'll want to either print a newline:

printf("enter the no.\n");

或显式刷新输出:

printf("enter the no.");
fflush(stdout);

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